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makkiz [27]
2 years ago
12

? Assessment

Computers and Technology
1 answer:
Ghella [55]2 years ago
8 0

Answer: Game designer, sound engineer, software engineer, writer, quality assurance tester

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Which of the following should be clicked to open Backstage View?
lora16 [44]

Answer:

File tab

Explanation:

source https://www.computerhope.com/jargon/b/backstage-view.htm

7 0
3 years ago
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How many times does the following loop execute?int upperCaseLetters = 0;String str = "abcdEfghI";boolean found = false;for (int
damaskus [11]

Answer:

Five times

Explanation:

Given the codes as follows:

  1.        int upperCaseLetters = 0;
  2.        String str = "abcdEfghI";
  3.        boolean found = false;
  4.        for (int i = 0; i < str.length() && !found; i++)
  5.        {
  6.            char ch = str.charAt(i);
  7.            if (Character.isUpperCase(ch))
  8.            {
  9.                found = true;
  10.            }
  11.        }

The for loop will stop when the first uppercase letter is found in the str. This condition is set in the for loop condition ( i < str.length() && !found)

Since the the first upper case letter is the fifth character in the given str, the for loop will run for five rounds. In the fifth round the condition in the if statement (Line 9) will be evaluated to true and then set the true value to found variable (Line 11). This will terminate the loop in the next iteration.

7 0
3 years ago
Design and implement a class dayType that implements the day of the week in a program. The class dayType should store the day, s
Afina-wow [57]

The code is implemented based on the given operations.

Explanation:

#include <iostream>

#include <string>

using namespace std;

class dayType

{ private:

 string day[7];

 string presentDay;

 int numofDays;

public:

 void setDay(string freshDay);

 void printDay() const;

 int showDay(int &day);

 int nextDay(int day);

 int prevDay(int day) const;

 int calcDay(int day, int numofDays);    

 dayType()

 {

  day[0] = "Sunday";

  day[1] = "Monday";

  day[2] = "Tuesday";

  day[3] = "Wednesday";

  day[4] = "Thursday";

  day[5] = "Friday";

  day[6] = "Saturday";

  presentDay = day[0];

  numofDays = 0;

 };

 ~dayType();

};

#endif

#include "dayType.h"

void dayType::setDay(string freshDay)

{

  presentDay = freshDay;

}

void dayType::printDay()

{

  cout << "Day chosen is " << presentDay << endl;

}

int dayType::showDay(int& day)

{

  return day;

}

int dayType::nextDay(int day)

{

day = day++;

if (day > 6)

 day = day % 7;

switch (day)

{

case 0: cout << "The successive day is Sunday";

 break;

case 1: cout << "The successive day is Monday";

 break;

case 2: cout << "The successive day is Tuesday";

 break;

case 3: cout << "The successive day is Wednesday";

 break;

case 4: cout << "The successive day is Thursday";

 break;

case 5: cout << "The successive day is Friday";

 break;

case 6: cout << "The successive day is Saturday";

 break;

}

cout << endl;

return day;

}

 

int dayType::prevDay(int day)

{

day = day--;

switch (day)

{

case -1: cout << "The before day is Saturday.";

 break;

case 0: cout << "The before day is Saturday.";

 break;

case 1: cout << "The before day is Saturday.";

 break;

case 2: cout << "The before day is Saturday.";

 break;

case 3: cout << "The before day is Saturday.";

 break;

case 4: cout << "The before day is Saturday.";

 break;

case 5: cout << "The before day is Saturday.";

 break;

default: cout << "The before day is Saturday.";

}

cout << endl;

return day;

}

int dayType::calcDay(int addDays, int numofDays)

{

addDay = addDays + numofDays;

if (addDay > 6)

 addDay = addDay % 7;

switch(addDay)

{

case 0: cout << "The processed day is Sunday.";

 break;

case 1: cout << "The processedday is Monday.";

 break;

case 2: cout << "The processedday is Tuesday.";

 break;

case 3: cout << "The processedday is Wednesday.";

 break;

case 4: cout << "The processedday is Thursday.";

 break;

case 5: cout << "The processedday is Friday.";

 break;

case 6: cout << "The processedday is Saturday.";

 break;

default: cout << "Not valid choice.";

}

cout << endl;

return addDays;

}

4 0
3 years ago
Implement a simplified version of a crypto broker platform. Initially, there is an array of users, with each user depositing onl
Salsk061 [2.6K]
Jriririiekeekekkksks
3 0
3 years ago
Ill mark you the brainleist and give you 50 points if you wanna chat
tekilochka [14]

sure! what do you wanna chat about?

6 0
3 years ago
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