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Vlada [557]
4 years ago
8

5-2x=-4x-7 ???????????????????????

Mathematics
2 answers:
IrinaK [193]4 years ago
8 0

My goodness !  What are you going to do when you
really need a question mark and you don't have any
because you used them all up ?

You said                                5 - 2x  =  -4x - 7

Add  4x  to each side:           5 + 2x  =        -7

Subtract  5  from each side:       2x  =       -12

Divide each side by  2 :               x  =         -6
 
svet-max [94.6K]4 years ago
3 0
+2x on both sides
5=-2x-7
+7
12=-2x
/-2
-6=x
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Paaaa hellllpppp po with solution po sana​
ira [324]
<h2>Solving Equations</h2>

To solve linear equations, we must perform inverse operations on both sides of the equal sign to <em>cancel values out</em>.

  • If something is being added to x, subtract it from both sides.
  • If something is being subtracted from x, add it on both sides.
  • Same with multiplication and division. If x is being divided, multiply. If x is being multiplied, divide.

We perform inverse operations to<em> combine like terms</em>. This means to get x to one side and everything else on the other.

<h2>Solving the Questions</h2><h3>Question 1</h3>

5x+7=15

Because 7 is being added to x, subtract it from both sides:

5x+7-7=15-7\\5x=8

Because x is being multiplied by 5, divide both sides by 5:

\dfrac{5x}{5}=\dfrac{8}{5}\\\\x=\dfrac{8}{5}

Therefore. x=\dfrac{8}{5}.

<h3>Question 2</h3>

7x+4=5x-18

Here, we can group all the x values on the left side of the equation. Subtract 5x from both sides:

7x+4-5x=5x-18-5x\\2x+4=-18

To isolate x, subtract 4 from both sides:

2x+4-4=-18-4\\2x=-22

Divide both sides by 2:

\dfrac{2x}{2}=\dfrac{-22}{2}\\\\x=-11

Therefore, x=-11.

6 0
2 years ago
Calculate the sum of the multiples of 4 from 0 to 1000
allochka39001 [22]

Answer:

sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

Step-by-step explanation:

This problem can be solved using concept of arithmetic progression.

The sum of n term terms in arithmetic progression is given by

sum = (2a+(n-1)d)n/2

where

a is the first term

d is the common difference of arithmetic progression

_____________________________________________________

in the problem

series is multiple of 4 starting from 4 ending at 1000

so series will look like

series: 0,4,8,12,16..................1000

a is first term so

here a is 0

lets find d the common difference

common difference is given by nth term - (n-1)th term

lets take nth term as 8

so (n-1)th term = 4

Thus,

d = 8-4 = 4

d  can also be seen 4 intuitively as series is multiple of four.

_____________________________________________

let calculate value of n

we have last term as 1000

Nth term can be described

Nth term = 0+(n-1)d

1000 =   (n-1)4

=> 1000 = 4n -4

=> 1000 + 4= 4n

=> n = 1004/4 = 251

_____________________________________

now we have

n = 1000

a = 0

d = 4

so we can calculate sum of the series by using formula given above

sum = (2a+(n-1)d)n/2

       = (2*0 + (251-1)4)251/2

       = (250*4)251/2

     = 1000*251/2 = 500*251 = 125,500

Thus, sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

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Answer:

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x = -3

Step-by-step explanation:

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