3 years ago

Find the center and the radius of the circle defined by the equation x^2-8x+y+12y+36=0

1 answer:

choli [55]3 years ago

3 0

Hello,
center is (4,-6)
radius=4
since
$x^2-8x+y^2+12y+36=0\\

x^2-2*4x+16-16+y^2+2*6y+36=0\\

(x-4)^2+(y+6)^2=4^2

$

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