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iragen [17]
3 years ago
15

Find the center and the radius of the circle defined by the equation x^2-8x+y+12y+36=0

Mathematics
1 answer:
choli [55]3 years ago
3 0
Hello,
center is (4,-6)
radius=4
since
x^2-8x+y^2+12y+36=0\\

x^2-2*4x+16-16+y^2+2*6y+36=0\\

(x-4)^2+(y+6)^2=4^2




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