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Semmy [17]
2 years ago
7

Evaluate the expression: 3a+4 a = 1.5 a = 1/3 a = 2

Mathematics
1 answer:
Nana76 [90]2 years ago
7 0

Answer:

mathpapa.com

the place i got this from tbh i don't understand what you want for an answer but i tried, so here is a website that i got these from i hope it helps you.

Step-by-step explanation:

Evaluate for a= 1/3

3(1/3)+4(1/3) = 7/3

Evaluate for a= 1.5

(3)(1.5)+(4)(1.5)

=10.5

Evaluate for a=

(3)(2)+(4)(2)

=14

You might be interested in
Solve the equation 16y+ -2=-20
Ilia_Sergeevich [38]

Answer:

y=-34

Step-by-step explanation:

16y-2=20

    +2   +2

16y=-18

-16    -16

y= -34

6 0
3 years ago
How many pounds are in 1 1/2 pounds and 8 ounces?
yaroslaw [1]

Answer:

2 pounds

Step-by-step explanation:

Because 8 ounces = 0.5 pounds

1.5+0.5=2

7 0
2 years ago
The amounts below represent the last twelve transactions made to Juan's checking account.Positive numbers represent deposits and
TiliK225 [7]

Answer:

Option B. Range of the given sample data is 113.

Step-by-step explanation:

The given question is incomplete; here is the complete question.

Find the range for the given sample data.

The amounts below represent the last twelve transactions made to Juan's checking account.  Positive numbers represent deposits and negative numbers represent debits from his account.

$28   -$20   $67   -$22   -$15   $17  -$38  $41   $53   -$13   $30   $75

Option A. $75

Option B. $113

Option C. $37

Option D. -$113

Transaction done by Juan can be arrange from lowest to highest

-38   -22   -20    - 15    -13    17   28    30   41   53    67    75    

Now we know rage of the sample data = Highest value - Lowest value

= 75 - (-38)

= 113

Therefore, range of the given sample data is 113.

Option B is the answer.

6 0
3 years ago
10x10 please its so hard aaaa
stellarik [79]

Answer:

its 55

Step-by-step explanation:

5 0
3 years ago
An appliance dealer's website features the mean life expectancy values for major household appliances. A standard refrigerator's
marshall27 [118]

Answer:

There is an 84% probability that your standard refrigerator will last between 12 and 20 years.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

A standard refrigerator's mean life expectancy is 18 years with a standard deviation of 2 years. This means that \mu = 18, \sigma = 2.

What is the probability that your standard refrigerator will last between 12 and 20 years?

This probability is the pvalue of Z when X = 20 subtracted by the pvalue of Z when X = 12. So

X = 20

Z = \frac{X - \mu}{\sigma}

Z = \frac{20 - 18}{2}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 12

Z = \frac{X - \mu}{\sigma}

Z = \frac{12- 18}{2}

Z = -3

Z = -3 has a pvalue of 0.0014

This means that there is a 0.8413-0.0014 = 0.8399 = 0.84 = 84% probability that your standard refrigerator will last between 12 and 20 years.

5 0
3 years ago
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