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diamong [38]
3 years ago
5

(4 x 6) +9. pls help me

Mathematics
2 answers:
Bond [772]3 years ago
7 0

Answer:

33

Step-by-step explanation:

(4x6)+9?

Ill take it as

(4*6)+9

4*6=24\\24+9=33

Contact [7]3 years ago
6 0

Step-by-step explanation:

(4 \times 6) + 9

Follow PEMDAS

24 + 9 \\  = 33

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Arlecino [84]

Answer: the correct one is C) found in the Philippines and resembling

Step-by-step explanation:

To maintain parallelism, you must list items with equal grammatical structure.

"Found" is just an adjective that modifies the animal, and so is "resembling." Sure, they don't sound the same, but they're both adjectives.  

4 0
3 years ago
Left Witch needs 3.25 gallons of "Toe of Frog" in her potion. If she can get half a gallon for $2.50, how much will she spend
Sladkaya [172]

Answer:

$16.25

Step-by-step explanation:

Half a gallon for $2.50 is the same as a quarter a gallon for $1.25.

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6 0
2 years ago
A dairy farm uses the somatic cell count (SCC) report on the milk it provides to a processor as one way to monitor the health of
Eva8 [605]

Answer:

t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37  

p_v =P(t_{4}>2.37)=0.038  

If we compare the p value and a significance level assumed \alpha=0.1 we see that p_v so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.  

Step-by-step explanation:

Data given and notation

\bar X=250000 represent the sample mean  

s=37500 represent the standard deviation for the sample

n=5 sample size  

\mu_o =210250 represent the value that we want to test  

\alpha=0.1 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses to be tested  

We need to conduct a hypothesis in order to determine if the mean is higher than 210250, the system of hypothesis would be:  

Null hypothesis:\mu \leq 210250  

Alternative hypothesis:\mu > 210250  

Compute the test statistic  

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

We can replace in formula (1) the info given like this:  

t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37  

Now we need to find the degrees of freedom for the t distirbution given by:

df=n-1=5-1=4

Conclusion

Since is a one right tailed test the p value would be:  

p_v =P(t_{4}>2.37)=0.038  

If we compare the p value and a significance level assumed \alpha=0.1 we see that p_v so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.  

6 0
3 years ago
Given that <img src="https://tex.z-dn.net/?f=a%5E%7Bb%7D" id="TexFormula1" title="a^{b}" alt="a^{b}" align="absmiddle" class="la
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Answer:

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5 0
3 years ago
What is the percentage of 100
tigry1 [53]
100%
hope that helps! :)
4 0
3 years ago
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