Solving a polynomial inequation
Solving the following inequation:
(x - 8) (x + 1) > 0
We are going to find the sign both parts of the multiplication,
(x - 8) and (x + 1), have when
x < - 8
-8 < x < 1
1 < x
Then we know (x - 8) (x + 1) > 0 whenever (x - 8) (x + 1) is positive
We can see in the figure (x - 8) (x + 1) is positive when x < -8 and x > 1
Then
Answer:B
Answer:
-6-b
Step-by-step explanation:
4(1-2b)+7b-10
Multiply what's in parantheses
4(1)=4
4(-2b)=-8b
4-8b+7b-10
Combine like terms
4-10 -8b+7b
-6-b
Hope this helps :)
1 triangle: 2*6 + 1*5
2 triangles: 2*6 + 2*5
3 triangles: 2*6 + 3*5
So for n triangles: p = 2*6 + n*5 = 12 + 5n
Answer: (x+7)^2 + (y-4)^2 = 121 or (x+7)^2 + (y-4)^2 = 11^2
Step-by-step explanation:
Equation of the circle is:
, which is the center 
and the radius 
-Place the center (-7,4) and radius 11 onto that equation:
(if simplified radius needed)
or
Answer:
Step-by-step explanation:
9. Yes
10. No
11. No
12. Yes
13. Yes
14. No
