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koban [17]
3 years ago
10

Adison earned $25 mowing her neighbor's lawn. Then she loaned her friend $18, and got $50 from her grandmother for her birthday.

She now has $86. How much money did Adison have to begin with?
Mathematics
1 answer:
Ber [7]3 years ago
4 0
She started with $7 because she gave away 18 then she got $50 then she has $57 then she got $29 then she has $86
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laila [671]

Answer: This is rly confusing

Step-by-step explanation:

5 0
3 years ago
Help what fudge doodles
vlabodo [156]

Answer:

{(-2, -7), (-1, -5), (0, -3), (1, -1), (2, 1)}

Step-by-step explanation:

Consider an element in the set we want to achieve. This element can be written as the ordered pair (x, y), where x comes from the set {-2, -1, 0, 1, 2} and given some value of x, we can find y (with the formula y = 2 * x - 3).

So to begin finding the set of all pairs in the resulting set, we first begin by listing out all values of x in each pair:

(-2, y)

(-1, y)

(0, y)

(1, y)

(2, y)

Now to find y, we use the formula y = 2 * x - 3, and we get

(-2, 2 * (-2) - 3)

(-1, 2 * (-1) - 3)

(0, 2 * (0) - 3)

(1, 2 * (1) - 3)

(2, 2 * (2) - 3)

which simplifies to

(-2, -7)

(-1, -5)

(0, -3)

(1, -1)

(2, 1)

5 0
3 years ago
Penny and her two friends each ate 1/6 of cake . how much cake did they eat
Tanya [424]
Penny + 2 friends = 3 people

3(1/6) = 3/6 = 1/2

They ate 1/2 of the cake.
4 0
3 years ago
A line of best fit is drawn for the set of points shown on the graph. Which point is an approximate extrapolation for x = 30 fro
Goshia [24]

Answer with explanation:

Equation of Linear Regression line is

 y=1.14 x + 3.805

A line of regression is that line which passes through none of the points, few points or all the points in the two dimensional coordinate plane.It tells value of one variable when another variable is known.

for, x=30

y=1.14 × 30 +3.805

y=34.20 +3.805

y=38.005

y=38 (approx)

So, Ordered pair is , (30,38)

Option B

8 0
3 years ago
Read 2 more answers
Use Lagrange multipliers to find the maximum and minimum values of f(x,y)=x+4y subject to the constraint x2+y2=9, if such values
Vesnalui [34]

The Lagrangian is

L(x,y,\lambda)=x+4y+\lambda(x^2+y^2-9)

with critical points where the partial derivatives vanish.

L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}

L_y=4+2\lambda y=0\implies y=-\dfrac2\lambda

L_\lambda=x^2+y^2-9=0

Substitute x,y into the last equation and solve for \lambda:

\left(-\dfrac1{2\lambda}\right)^2+\left(-\dfrac2\lambda\right)^2=9\implies\lambda=\pm\dfrac{\sqrt{17}}6

Then we get two critical points,

(x,y)=\left(-\dfrac3{\sqrt{17}},-\dfrac{12}{\sqrt{17}}\right)\text{ and }(x,y)=\left(\dfrac3{\sqrt{17}},\dfrac{12}{\sqrt{17}}\right)

We get an absolute maximum of 3\sqrt{17}\approx12.369 at the second point, and an absolute minimum of -3\sqrt{17}\approx-12.369 at the first point.

4 0
3 years ago
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