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Alex Ar [27]
3 years ago
13

What is the simplified slope of the line that passes through points A(6,0) B(0,-2)?

Mathematics
1 answer:
Zigmanuir [339]3 years ago
4 0
To find slope, use the equation:
slope = \frac{ y_{2} - y_{1} }{x_{2}-x_{1}}<span>
<span>where x_{2} and y_{2} are the x and y values of one coordinate point, and x_{1} and y_{1} are the x and y values of another coordinate point . Since we are given two coordinate points, that means we can find the slope using the slope equation.

</span></span>

Let's choose (6, 0) as your (x_{2},&#10;y_{2}) point and (0, -2) as your (x_{1}, y_{1}) point, but you can switch those if you want! That makes x_{2} = 6, y_{2} = 0 and x_{1} = 0, y_{1} = -2. Plug these values into the slope equation and simplify:

\frac{ y_{2} - y_{1} }{x_{2}-x_{1}} \\&#10; = \frac{ 0 - (-2) }{6-0} \\&#10; = \frac{2}{6} \\&#10;=  \frac{1}{3}


-----


Answer: Slope = \frac{1}{3}

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• rewrite tan = sin/cos

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• expand the functions of 2<em>A</em> using the double angle identities

… = 2/(2 cos²(<em>A</em>) - 1) (sin(<em>A</em>) cos(<em>A</em>) + sin(<em>A</em>) cos(<em>A</em>) (cos²(<em>A</em>) - sin²(<em>A</em>)))

• factor out sin(<em>A</em>) cos(<em>A</em>)

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• simplify the last factor using the Pythagorean identity, 1 - sin²(<em>A</em>) = cos²(<em>A</em>)

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• rearrange terms in the product

… = 2 sin(<em>A</em>) cos(<em>A</em>) (2 cos²(<em>A</em>))/(2 cos²(<em>A</em>) - 1)

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• rewrite cos = 1/sec, i.e. sec = 1/cos

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• divide through again by cos²(<em>A</em>)

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• rewrite sin/cos = tan and 1/cos = sec

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• factor out sec²(<em>A</em>) in the denominator

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• rewrite using the Pythagorean identity, sec²(<em>A</em>) = 1 + tan²(<em>A</em>)

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(Note that some of these steps are optional or can be done simultaneously)

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