What type of rock is formed from other rocks being subjected to great heat and pressure?
1 answer:
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Answer:
Check the explanation
Explanation:
myString. h:
#include <iostream>
using namespace std;
#ifndef _MYSTRING_H_
#define _MYSTRING_H_
class myString{
private:
char *str;
public:
myString();
myString(const char *s);
void operator = (myString &s);
int length();
friend ostream &operator <<(ostream &out, myString &s);
friend istream &operator >>(istream &out, myString &s);
bool operator <(myString &s);
bool operator <=(myString &s);
bool operator >(myString &s);
bool operator >=(myString &s);
bool operator ==(myString &s);
bool operator !=(myString &s);
};
#endif
myString. cpp:
#include "myString. h"
#include <cstring>
myString::myString(){
str = new char;
str[0] = '\0';
}
myString::myString(const char *s){
int len = strlen(s);
str = new char[len + 1];
for(int i = 0; i < len; ++i){
str[i] = s[i];
}
str[len] = '\0';
}
void myString::operator = (myString &s){
s.str = new char[length() + 1];
for(int i = 0; i < length(); ++i){
s.str[i] = str[i];
}
s.str[length()] = '\0';
}
int myString::length(){
return strlen(str);
}
ostream &operator <<(ostream &out, myString &s){
out << s.str;
return out;
}
istream &operator >>(istream &in, myString &s){
in >> s.str;
return in;
}
bool myString::operator < (myString &s){
return strcmp(str, s.str) < 0;
}
bool myString::operator <= (myString &s){
return strcmp(str, s.str) <= 0;
}
bool myString::operator > (myString &s){
return strcmp(str, s.str) > 0;
}
bool myString::operator >= (myString &s){
return strcmp(str, s.str) >= 0;
}
bool myString::operator == (myString &s){
return strcmp(str, s.str) == 0;
}
bool myString::operator != (myString &s){
return strcmp(str, s.str) != 0;
}
main. cpp:
#include "myString.h"
#include <iostream>
using namespace std;
int main(){
myString s1, s2;
cout << "Enter first string: ";
cin >> s1;
cout << "Enter second string: ";
cin >> s2;
cout << "you entered: " << s1 << " and " << s2 << endl;
myString s3 = s1;
cout << "Value of s3 is " << s3 << endl;
if(s1 < s2){
cout << s1 << " < " << s2 << endl;
}
if(s1 <= s2){
cout << s1 << " <= " << s2 << endl;
}
if(s1 > s2){
cout << s1 << " > " << s2 << endl;
}
if(s1 >= s2){
cout << s1 << " >= " << s2 << endl;
}
if(s1 == s2){
cout << s1 << " == " << s2 << endl;
}
if(s1 != s2){
cout << s1 << " != " << s2 << endl;
}
return 0;
}
Kindly check the output below.
Answer:
"64" is the output of the above code.
Explanation:
- The function holds the expression with (**) operator which is used to calculate the power in python language.
- So if we write 2**4, then this will give 16 as output. It is because when we calculate the
, then it will become 16.
- The above question passes the num1 and num2 value in the function as an argument which is 3 and 4.
- So 3 will be initialized for x variable and 4 is for y variable.
- So when we calculate
then it will become
which will become 16.
- So 64 is the output for the above question.