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Lady_Fox [76]
2 years ago
6

What to do if you forgot your locked notes password

Computers and Technology
2 answers:
rodikova [14]2 years ago
5 0

Answer:

I don't have a Apple, but I suggest you either contact Apple Help, or go to settings and see if you can reset it.

Add-on:

I hope this helped you at all.

marshall27 [118]2 years ago
4 0

Answer:

what you can probably do is go to an Apple store and book an appointment with the Genius Bar and tell them your problem to see if they can help you recover your password.

i hope this helps :D

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Write the definition of a method named countPos that receives a reference to a Scanner object associated with a stream of input
NNADVOKAT [17]

Answer:

Here is the method countPos    

  static int countPos(Scanner input){ //method that takes a reference to a Scanner object

   int counter=0;  // to count the positive integers  

   int number; //to store each integer value

   if(input.hasNextInt()){ //checks if next token in this scanner input is an integer value

       number=input.nextInt(); //nextInt() method of a Scanner object reads in a string of digits and converts them into an int type and stores it into number variable

       counter=countPos(input); //calls method by passing the Scanner object and stores it in counter variable

       if(number>0) //if the value is a positive number

           counter++;    } //adds 1 to the counter variable each time a positive input value is enountered

   else    { //if value is not a positive integer

       return counter;    } //returns the value of counter

   return counter; } //returns the total count of the positive numbers

Explanation:

Here is the complete program:

import java.util.Scanner; //to take input from user

public class Main { //class name

//comments with each line of method below are given in Answer section

static int countPos(Scanner input){

   int counter=0;

   int number;

   if(input.hasNextInt()){

       number=input.nextInt();

       counter=countPos(input);

       if(number>0)

           counter++;    }

   else    {

       return counter;    }

   return counter; }

public static void main(String[] args) { //start of main function

       System.out.println("Number of positive integers: " + countPos(new Scanner(System.in)));  } } //prints the number of positive integers by calling countPos method and passing Scanner object to it

The program uses hasNextInt method that returns the next token (next input value) and if condition checks using this method if the input value is an integer. nextInt() keeps scanning the next token of the input as an integer. If the input number is a positive number then the counter variable is incremented to 1 otherwise not. If the use enters anything other than an integer value then the program stops and returns the total number of positive integers input by the user. This technique is used in order to avoid using any loop. The program and its output is attached

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3 years ago
Compare GBN, SR, and TCP (no delayed ACK). Assume that the timeout values for all three protocols are sufficiently long such tha
kvv77 [185]

Answer and Explanation:

a)

For Go-Back-N:

  Host A sent total number of segments is 9.The initial segment numbers are 1,2,3,4,5 and re-sent the segemnts 2,3,4 and 5 because 2nd segment was lost.

Host B sent the number of ACKs are 8.Host B sent ACKs 1 by four times because 2nd segment was lost and sent 4ACKs with sequence numbers 2,3,4 and 5

selective repeat:

 Host A sent total number of segments is 6.The initial segment numbers are 1,2,3,4,5 and re-sent the segemnts 2 because 2nd segment was lost.

Host B sent the number of ACKs are 5.Host B sent four ACKs with sequence numbers 1,3,4,5 and re-sent ACK2 with sequence number 2 because 2nd segment was lost.

TCP :

Host A sent total number of segments is 6.The initial segment numbers are 1,2,3,4,5 and re-sent the segemnts 2 because 2nd segment was lost.

Host B sent the number of ACKs are 5.Host B sent four ACKs with sequence number 2 and There is one ACK with sequence number 6.TCP always send an ACK with expected sequence number

b) If the timeout values for all three protocol are much longer than 5*RTT,then TCP protocol successfully delivers all five data segments in shortest time interval.

 

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