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2 years ago

Question 2

Mathematics

1 answer:

Brums [2.3K]2 years ago

5 0

Answer is c I took the test

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Can someone please help me figure out how to do this problem. We have tried several different ways and none of them come up as b

Ilya [14]

Answer:

Step-by-step explanation:

Order of operations: PEMDAS (parentheses, exponents, multiplication, division, addition, subtraction)

5(9)+2(6) ÷ 3 + $5^{2}$

= 45+12÷ 3 +25

=45+4+25

=74

8 0

2 years ago

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Which line is most likely to have a slope of 10 ?

hodyreva [135]

The line that is most likely to have a slope of 10 is the second one down

6 0

3 years ago

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I need help it’s due in 10 mins ASAP I’ll mark you as a brainlist please help

Lady_Fox [76]

Take DEBC a parralelogram
Parralel sides are DE and BC
THEREFORE,
1/2*(a+b)*h
1/2*(6+15)*h
1/2*(21)*h=0
10.5*h=0
h=-10.5

3 0

3 years ago

A rectangular prism had a volume of 252 cubic centimeters. The length of the prism is 14 centimeters and the width of the prism

mojhsa [17]

<h2>Answer:</h2>

A prism is a solid object having two identical bases, hence the same cross section along the length. Prism are called after the name of their base. A rectangular prism is a solid whose base is a rectangle. Multiplying the three dimensions of a rectangular prism: length, width and height, gives us the volume of a prism:

$V=L\times W\times H$

FOR THE ORIGINAL PRISM WE HAVE THE FOLLOWING DIMENSIONS:

$L=14cm \\ \\ W=6cm \\ \\ H=3cm$

In fact, the volume is $252cm^3$ because:

$V=14\times 6\times 3 \therefore V=252cm^3$

Now the height of the prism was changed from 3 centimeters to 6 centimeters to create a new rectangular prism, therefore:

FOR THE NEW PRISM WE HAVE THE FOLLOWING DIMENSIONS:

$L=14cm \\ \\ W=6cm \\ \\ H=6cm$

So the new volume is:

$V=14\times 6\times 6 \therefore V=504cm^3$

<h3>What do we know about the volume of the new prism?</h3>

Well, the volume has increased from $252cm^3 \ to \ 504cm^3$ and since $504=2\times 252$ we can say that the new volume is two times the original volume.

8 0

2 years ago

When BA=10 ft, find the area of the region that is NOT shaded. Round to the nearest whole number. (reply so i can draw it out, p

nexus9112 [7]

The area of the region that is not shaded in the diagram is determined through the following solution:

A = (1 − (60°/360°)*π) * (10 ft ) ^2 A = 56*π*100 [ft2] A = 250/3 π [ft2]
A = 262 [ft2]

5 0

2 years ago