Hello,
If we want to factor the expression, we have to solve
3x² + 10x + 8 = 0
a = 3 ; b = 10 ; c = 8
∆ = b² - 4ac = 10² - 4 × 3 × 8 = 4 > 0
x1 = (-b - √∆)/2a = (-10 - 2)/6 = -12/6 = -2
x2 = (-b + √∆)/2a = (-10 + 2)/6 = -8/6 = -4/3
Factor :
a (x - x1)(x - x2)
= 3(x + 2)(x + 4/3)
= (x + 2)(3x + 4)
Is there another part to your question
<h2>SOLVING</h2>
Find the gradient of the line segment between the points 
The formula used, here is
Now let's put in the co-ordinates from these two points.
| subtract on top & bottom
| divide
Newton's Law of cooling is a differential equation that is simplified by using limits in temperature and time. The simplified equation is:
ln(T-Ts) = ln(T0-Ts) - kt
where
T is the final temperature
T0 is the initial temperature
Ts is the temperature of the surroundings
t is the time
k is a constant
Substituting the values:
ln(T-70) = ln(200-70) - (0.6)(2)
T = 109.16°F
The answer is B.
