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alina1380 [7]
3 years ago
15

PLEASE HELP ME!!! I AM SO CONFUSE!!!

Mathematics
1 answer:
Volgvan3 years ago
8 0
Multiply both sides by (3*5)
5(2n)=3(n+14)
distribute
10n=3n+42
minus 3n both sides
7n=42
divide both sides by 7
n=6
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your friend's house is 7.5 miles north and 10 miles west of the zoo. How far is your friend's house from the zoo?
maria [59]

Answer:

2.5 miles

Step-by-step explanation:

3 0
3 years ago
PLs help 50 PTS!!!!! PLEASE ILL GIVE BRAINLIEST!!!!!
Nookie1986 [14]

Answer:

\large\boxed{y=\dfrac{1}{4}x^2-x-4}

Step-by-step explanation:

The equation of a parabola in vertex form:

y=a(x-h)^2+k

<em>(h, k)</em><em> - vertex</em>

The focus is

\left(h,\ k+\dfrac{1}{4a}\right)

We have the vertex (2, -5) and the focus (2, -4).

Calculate the value of <em>a</em> using k+\dfrac{1}{4a}

<em>k = -5</em>

-5+\dfrac{1}{4a}=-4        <em>add 5 to both sides</em>

\dfrac{1}{4a}=1           <em>multiply both sides by 4</em>

4\!\!\!\!\diagup^1\cdot\dfrac{1}{4\!\!\!\!\diagup_1a}=4

\dfrac{1}{a}=4\to a=\dfrac{1}{4}

Substitute

a=\dfrac{1}{4},\ h=2,\ k=-5

to the vertex form of an equation of a parabola:

y=\dfrac{1}{4}(x-2)^2-5

The standard form:

y=ax^2+bx+c

Convert using

(a-b)^2=a^2-2ab+b^2

y=\dfrac{1}{4}(x^2-2(x)(2)+2^2)-5\\\\y=\dfrac{1}{4}(x^2-4x+4)-5

<em>use the distributive property: a(b+c)=ab+ac</em>

y=\left(\dfrac{1}{4}\right)(x^2)+\left(\dfrac{1}{4}\right)(-4x)+\left(\dfrac{1}{4}\right)(4)-5\\\\y=\dfrac{1}{4}x^2-x+1-5\\\\y=\dfrac{1}{4}x^2-x-4

3 0
3 years ago
Find the missing side of the right triangle. Round to the nearest 10th if necessary:
denpristay [2]
M=12.2
(7^2)+(10^2)=149
the square root of 149 is 12.2
3 0
3 years ago
In a batch of 960 calculators, 8 were found to be defective. What is a probability that a calculator chosen at random will be de
DaniilM [7]
Out of 960 calculators, 8 were found be to defective

Probability:
                 \frac{8}{960}
                 0.00833...
As a Percent:
                 0.00833....× 100
                 0.833%
To the nearest tenth of percentage:
                 0.833% ≈ 0.8%
8 0
3 years ago
Read 2 more answers
If the hypotenuse of a right triangle is 20 cm and one of the legs is 16 cm, how long is the other leg?
siniylev [52]
Because this is a triangle and we know that we can use the Pythagorean Theorem to find the hypotenuse we just plug in the numbers. But because you have the hypotenuse already you will subtract the leg from the hypotenuse.

A^2+B^2=C^
16^2+B^2=20^2
256+B^2=400 subtract 256 from both sides
B^2=144 now take the square root of both sides
B=12

The second leg is 12 cm long. Your answer is B, the second answer.
6 0
3 years ago
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