Question

I am in some serious need of help If P(a)=1/3, P(b)=2/5, and P(AuB)=3/5 what is P=(AnB)?

Answer 1

$P(A\cap B)=P(A)+P(B)-P(A\cup B)$

$\implies P(A\cap B)=\dfrac13+\dfrac25-\dfrac35=\dfrac2{15}$

Answer 2

Answer:

The value of P=(AnB) is $\frac{2}{15}$.

Step-by-step explanation:

It is given that

$P(A)=\frac{1}{3}$

$P(B)=\frac{2}{5}$

$P(A\cap B)=\frac{3}{5}$

According to the union formula:

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

$P(A\cup B)=\frac{1}{3}+\frac{2}{5}-\frac{3}{5}$

$P(A\cup B)=\frac{1}{3}+\frac{2-3}{5}$

$P(A\cup B)=\frac{1}{3}-\frac{1}{5}$

$P(A\cup B)=\frac{5-3}{15}$

$P(A\cup B)=\frac{2}{15}$

Therefore the value of P=(AnB) is $\frac{2}{15}$.