After 300 miles.
35+0.1x= 25+0.15x
<u> -0.1x -.01x</u> (0.1- 0.1 crosses out)
35= 25+0.15x
<u> -25 -25 </u> (25- 25 crosses out)
15= 0.15x
15/0.15= 0.15x/0.15 (crosses out)
300= x
The question ask to find the rate of change of the distance from the paticle to the origin at this instant where as a particle is moving along the curve y = 5sqrt(5x+4) and base on my calculation, I came up with an answer of 254/sqrt(226). I hope you are satisfied with my answer and feel free to ask for more
The answer to 188x31 is 5,828
Answer:
(2)
Step-by-step explanation:
Our logarithmic expression is: 
.
Remember the logarithmic property that ln(a/b) = lna - lnb. So, we can write this as:
Also, we can write square roots as powers of one-half, so √e = 
. There's another log property that: 
. We can apply that here for both the √e and the y³:
Finally, note that ln(e) is just 1, so we have:
The answer is thus (2).
<em>~ an aesthetics lover</em>
