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butalik [34]
3 years ago
8

According to government data, the probability that a woman between the ages of 25 and 29 was never married is 40%. in a random s

urvey of 10 women in this age group, what is the probability that two or fewer were never married
Mathematics
1 answer:
givi [52]3 years ago
7 0
The probability of finding 2 never married
10c2*0.4^2*0.6^8=
the probability of finding 1 never married
10C1*0.4*0.6^9=
the probability of finding 0 never married
10C0*0.6^10=

the answer is all the above answers added together.
think you can do the rest of the calculation by yourself. :)

btw nCr=n!/(n-r)!r!
good luck
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vampirchik [111]
Define natural hazard?

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What is the difference between tectonic hazards and weather hazards ?

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4 0
3 years ago
What times what times what times what equals -5/24 i need two different ways please help
saul85 [17]

Answer:

;fjk;rofkfk;;fkslgl;fkfls'rfi;,dfei;se;feieirjeiljlaejre

sfe;jflejflseleijflskfeselselehf

Step-by-step explanation:

ueufaepfsfjseuefkeou;oiwrrsdkuijksgukuisdjyfekefaehkf

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B5%7D%20y%3D32%5C%5C" id="TexFormula1" title="\frac{4}{5} y=32\\" alt="\frac{4
lys-0071 [83]

so the answer is.. 40

hope it is helpfull..

3 0
3 years ago
What is the solution of x=2+ sqrt x-2
wariber [46]

Answer:

C

Step-by-step explanation:

x=2+\sqrt{x-2} \\\\x-2=\sqrt{x-2} \\\\(x-2)^2=\pm(x-2) \\\\x^2-4x+4=\pm(x-2) \\\\

x^2-5x+6=0 OR x^2+3x+2=0

x=2 and 3

Hope this helps!

4 0
3 years ago
Read 2 more answers
The bulls-eye on a target has a diameter of 3 inches. The whole target has a diameter of 15 inches. What part of the whole targe
Helga [31]
Since a target is a circle and the bulls-eye is also a circle, the percent of the circle that is bulls-eye would be (Area of the bulls eye)/(Area of the target)

[tex] A = \pi r^{2} \\
d = 2r \\ r = \frac{d}{2} \\\\
\frac{ \pi ( \frac{d}{2})^{2}}{ \pi ( \frac{d}{2})^{2} }= \frac{ \pi ( \frac{3}{2})^{2}}{ \pi ( \frac{15}{2})^{2} }\\
\frac{ \pi ( \frac{3}{2})^{2} }{ \pi ( \frac{15}{2})^{2} } = \frac{ \pi (1.5)^{2} }{ \pi (7.5)^{2} } \\
\frac{ \pi (1.5)}{ \pi (7.5) } = \frac{ \pi (2.25)}{ \pi (56.25)}\\
\frac{ \pi (2.25)}{ \pi (56.25)}=\frac{2.25}{56.25}= 0.04 [tex]

So the bulls-eye takes up 4% of the target.
4 0
3 years ago
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