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natta225 [31]
3 years ago
8

Does the parabola with equation x2– x + 6 = 0 have real or imaginary roots?

Mathematics
1 answer:
podryga [215]3 years ago
3 0

imaginary roots

to check the nature of the roots of a parabola in standard form :

ax² + bx + c = 0 : ( a ≠ 0 ) use the discriminant b² - 4ac

• If  b² - 4ac > 0 then roots are real and distinct

• If b² - 4ac = 0 then roots are real and equal

• If b² - 4ac < 0 then roots are not real

for x² - x + 6 = 0 with a = 1, b = - 1, c =  6

b² - 4ac = ( -1)² - (4 × 1 ×  6 ) = 1 - (  24 ) = 1 - 24 = - 23

since b² - 4ac < 0 then roots are not real ( imaginary )



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AfilCa [17]

Answer:

<em> Linear model </em>

The function f(x) which represents the total amount in the savings account in x months is given by:           f(x)=25x+2000

Step-by-step explanation:

Given:

Enrico deposited $2000 in a savings account.

Each month he will deposit additional $25.

This shows that the rate at which the amount is increasing each month is constant.

Therefore, the model will be  linear with a slope 25.

So , if x represents the number of months.

and f(x) represents the corresponding amount in the account.

Then the function f(x) is given by: f(x)=25x+2000

3 0
3 years ago
Angus has $3,000 he want to invest. What interest rate compounded continuously does an account need to offer so that Angus has $
kaheart [24]

Answer:

The interest rate is 7.58%

Step-by-step explanation:

Compound continuous interest can be calculated using the formula:

A = Pe^{rt}, where

  • A is the future value of the investment, including interest
  • P is the principal investment amount (the initial amount)
  • r is the interest rate  in decimal
  • t is the time the money is invested for

∵ Angus has $3,000 he want to invest

∴ P = 3000

∵ The interest rate is compounded continuously

∵ Angus has $5,500 in 8 years

∴ A = 5500

∴ t = 8

→ Substitute them in the rule above to find r

∵ 5500 = 3000e^{8r}

→ Divide both sides by 3000

∴ \frac{11}{6} = e^{8r}

→ Insert ㏑ in both sides

∵ ㏑( \frac{11}{6} ) = ㏑(e^{8r})

→ Remember ㏑(e^{n}) = n

∴ ㏑( \frac{11}{6} ) = 8r

→ Divide both sides by 8

∴ 0.07576697545 = r

→ Multiply it by 100% to change it to a percentage

∴ r = 0.07576697545 × 100%

∴ r = 7.576697545 %

→ Round it to the nearest hundredth

∴ r ≅ 7.58

∴ The interest rate is 7.58%

3 0
2 years ago
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andrezito [222]

Answer:

Hope this Helped ;-;

Step-by-step explanation:

75 is the Answer but the closet is 70

6 0
3 years ago
Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains 200 L of a dye solution with a
In-s [12.5K]

Answer: t= 460.52 minutes

Step-by-step explanation:Q'=Q/100

Q'= rate in and out of water

Finding the differential equation

Let Q'(t)= The quantity of dye in the tank for t time

But rate in=0 Q/200 ×2=Q'

Q'/Q=-1/100

Dividing by Q gives

Ln/Q/ + c = -1/100 + c1

Integrating both sides gives

Ln/Q/ = -(1/100)t + c2

But c+c1=C2= A constant

Q=C2e(-t/100)

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4 0
3 years ago
In a large school district, 16 of 85 randomly selected high school seniors play a varsity sport. in the same district, 19 of 67
Mashcka [7]

Answer:

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Step-by-step explanation:

Its given that : In a large school district, 16 of 85 randomly selected high school seniors play a varsity sport

\implies P_1=\frac{16}{85}\\\\n_1=85

Also, in the same district, 19 of 67 randomly selected high school juniors play a varsity sport

\implies P_1=\frac{19}{67}\\\\n_2=67

Now, finding the standard error of the difference :

\text{Standard Error = }\sqrt{\frac{P_1(1-P_1)}{n_1}+\frac{P_2(1-P_2)}{n_2}}\\\\\implies \text{Standard Error = }\sqrt{\frac{\frac{16}{85}(1-\frac{16}{85})}{85}+\frac{\frac{19}{67}(1-\frac{19}{67})}{67}}\\\\\implies\text{Standard Error = }0.0695

Hence, Standard Error of the difference = 0.0695

6 0
3 years ago
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