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Mars2501 [29]
3 years ago
13

Ervin sells vintage cars. Every three months, he manages to sell 13 cars. Assuming he sells cars at a constant rate, what is the

slope of the line that represents this relationship if time in months is along the x-axis and the number of cars sold is along the y-axis?
Mathematics
2 answers:
joja [24]3 years ago
8 0
(3,13) is the simplest slope then increases to (6,26), (9,39) And continues.
GaryK [48]3 years ago
7 0
What we know:

x-axis is months and we can set it up as increments of 3 months since he sells 13 cars every three months

y-axis is cars sold and we can set it up as increments of 13

slope=rise/run 
At 0 months we sold 0 cars and at 3 months we sold 13 cars. So, from point (0,0) we can do rise over run to reach the point (3,13). We rise 13 and run right 3. 

slope=rise/run=13/3


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1 year ago
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yan [13]
You can graph that by looking at the y-intercept first. That's where you start to put a point in the coordinate plane or graph.

So go down 1 below 0.

Next, look at the slope.
We know that y = -2x - 1 is in slope intercept form (y = mx+b)
So -2 is our slope. It will be -2/1 because we need a fraction to graph the rise over run and all whole numbers can be a fraction by making 1 as their denominator.

Look at the attachment. 

Starting from -1 (y-intercept), go down 2 (-2) then right 1 (1).
To complete the line above, keep the same value and reverse their sign/symbol. So -2/1 will be 2/-1. It goes up 2 then left 1.

I hope you understand and find this answer the most helpful! :)

8 0
3 years ago
Please help ASAP
babymother [125]
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3 0
3 years ago
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5/9*18/25<br><br> i need help
Akimi4 [234]

Answer:

\frac{2}{5}

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Please help me on this and show me the steps to the answer.
Julli [10]
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e = - 1/2


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