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Advocard [28]
3 years ago
8

True or false

Mathematics
1 answer:
miskamm [114]3 years ago
5 0

Answer:

1 is true

2 is true

3 is true

4 is false

5 is true

6 is true

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Six less than 2 times “y” is 34 equation form
wel
2y-6=34 is the needed equation
8 0
3 years ago
Read 2 more answers
2. How many terms are there in the expression: 3a + 6
Aliun [14]

Answer: 2

Step-by-step explanation: That expression is a binomial in any case the terms in a polynomial are separated by a plus or minus sign (+,-) so you can determine the number of terms by counting how many number or variable are being separated (ex: 3a+a-1 would have 3 terms and be a trinomial)

8 0
3 years ago
What is the equation of M=3,x=4,and b=9
natita [175]

Answer:

21=3(4)+9

Step-by-step explanation:

Assuming that the equation that you are trying the get is y=mx+b, plug in m, x, and b to get:

y=3(4)+9

y=12+9

y=21

Please be more specific so that you get the answer you need

6 0
3 years ago
A car is driving at a speed of 40 mi/h. What is the speed of the car in feet per minute? a. 2,400 ft/min b. 211,200 ft/min c. 3,
SCORPION-xisa [38]

Answer:

  3520 ft/min

Step-by-step explanation:

40 mi/h = (40 mi/h)×(5280 ft/mi)×(1 h)/(60 min) = 3520 ft/min

_____

Each conversion factor has a value of 1 (numerator = denominator), so changes the units without changing the speed.

3 0
3 years ago
George and Riley are selling fruit for a school fundraiser. Customers can buy small boxes of oranges and large boxes of oranges.
worty [1.4K]

The cost of small box of oranges is $7.

The cost of large box of oranges is $13.

<u>Step-by-step explanation:</u>

It is given that,

3 small boxes of oranges and 14 large boxes of oranges for a total of $203.

11 small boxes of oranges and 11 large boxes of oranges for a total of $220.

Let us take,

  • The cost of small box of oranges = x
  • The cost of large box of oranges = y

<u>The system of equations are framed as :</u>

3x + 14y = 203  ---------(1)

11x + 11y = 220  ---------(2)

<u>To solve these equations for x and y values :</u>

Multiply equation (1) by 11 and equation (2) by 3

Subtract eq(2) from eq(1),

 33x + 154y = 2233

- <u>(33x + 33y = 660)  </u>

  <u>        121 y = 1573  </u>

⇒ y = 1573 / 121

⇒ y = 13

∴ The cost of large box of oranges is $13.

Substitute y=13 in the eq(1),

⇒ 3x + 14(13) = 203

⇒ 3x + 182 = 203

⇒ 3x = 203 - 182

⇒ 3x = 21

⇒ x = 21 / 3

⇒ x = 7

∴ The cost of small box of oranges is $7.

<u />

7 0
3 years ago
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