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Advocard [28]
2 years ago
8

True or false

Mathematics
1 answer:
miskamm [114]2 years ago
5 0

Answer:

1 is true

2 is true

3 is true

4 is false

5 is true

6 is true

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An unknown number y is 12 more than an unknown number x. The number y is also x less than 17. The equations to find x and y are
grandymaker [24]

Answer:

d because then you can solve for y then use your answer to find x

4 0
3 years ago
Read 2 more answers
A driver averages 42 miles per hour and took 15 hours to travel between two cities what is the distance between the two cities
pishuonlain [190]

Answer:

The distence bettween the two cities is 630miles

Step-by-step explanation:

So you take 42 and multiply it by 15 and you get 630.

5 0
3 years ago
(05.01)Which equation can be used to calculate the area of the shaded triangle in the figure below?
Lemur [1.5K]
2nd one, take area of whole 12 x 4=48, if area is equally divided, divide area by 2 or multiply by 1/2

7 0
3 years ago
Read 2 more answers
What is the slope and y-intercept of this line?
RUDIKE [14]
THE SLOPE IS 1 AND THE Y INTERCEPT IS -3, the x is equal to 1, and the -3 is in the place of the y intercept so your answer would be A.
6 0
2 years ago
According to the manufacturer of the candy Skittles, 20% of the candy produced are red. If we take a random sample of 100 bags o
igomit [66]

Answer:

Probability that the proportion in our sample of red candies will be less than 20% is 0.5 .

Step-by-step explanation:

We are given that 20% of the candy produced are red. A random sample of 100 bags of Skittles is taken.

The distribution we can use here is;

               \frac{\hat p - p}{\sqrt{\frac{\hat p (1- \hat p)}{n} } } ~ N(0,1)

where, p = 0.20 and n = 100

Let \hat p = proportion of red candies in our sample

So, P(\hat p < 0.20) = P(\frac{\hat p - p}{\sqrt{\frac{\hat p (1- \hat p)}{n} } } < \frac{0.20 - 0.20}{\sqrt{\frac{0.2 (1- 0.2)}{100} } } ) = P(Z < 0) = 0.5

Therefore, probability that the proportion in our sample of red candies will be less than 20% is 0.5 .

5 0
3 years ago
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