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LenaWriter [7]
3 years ago
14

The length of the hypotenuse of a right triangle is 14 inches. If the length of one leg is 6 inches, what is the approximate len

gth of the other leg?
A. 11.5 inches B. 12.6 inches C. 15.2 inches D. 20.0 inches
Mathematics
2 answers:
Anvisha [2.4K]3 years ago
7 0
According to pythagoras theorem, 14^2 = 6^2 + side^2

=> the other side would be= 12.64 inches
OleMash [197]3 years ago
4 0

Answer:

The answer is B.) 12.6 inches

Step-by-step explanation:

other leg = 14^2 - 6^2

other leg = 196 - 36

other leg = (square root of) 160

other leg = 12.65

<u><em>So, the answer is B.) 12.6 inches.</em></u>

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The result is x^2 +x +4 -21/(x+3).

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Find the derivative of <br><img src="https://tex.z-dn.net/?f=%20y%20%3D%20%5Csqrt%5B3%5D%7Bx%7D%20" id="TexFormula1" title=" y =
MAXImum [283]

Answer:

\displaystyle y'(27) = \frac{1}{27}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Exponential Rule [Root Rewrite]: \displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}
  • Exponential Rule [Rewrite]: \displaystyle b^{-m} = \frac{1}{b^m}

<u>Calculus</u>

Derivatives

Derivative Notation

Basic Power Rule

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

<u>Step 1: Define</u>

y = ∛x

x = 27

<u>Step 2: Differentiate</u>

  1. [Function] Rewrite [Exponential Rule - Root Rewrite]:                               \displaystyle y = x^{\frac{1}{3}}
  2. Basic Power Rule:                                                                                         \displaystyle y' = \frac{1}{3}x^{\frac{1}{3} - 1}
  3. Simplify:                                                                                                         \displaystyle y' = \frac{1}{3}x^{-\frac{2}{3}}
  4. Rewrite [Exponential Rule - Rewrite]:                                                           \displaystyle y' = \frac{1}{3x^{\frac{2}{3}}}

<u>Step 3: Solve</u>

  1. Substitute<em> </em>in <em>x</em> [Derivative]:                                                                           \displaystyle y'(27) = \frac{1}{3(27)^{\frac{2}{3}}}
  2. Evaluate exponents:                                                                                     \displaystyle y'(27) = \frac{1}{3(9)}
  3. Multiply:                                                                                                         \displaystyle y'(27) = \frac{1}{27}

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

8 0
3 years ago
Pleaseeee helpp answer correctly !!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!
Pavel [41]

Answer:

x = 87º

Step-by-step explanation:

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