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JulsSmile [24]
4 years ago
9

Marie has renters insurance that she must pay twice a year. If each payment is $96, how much money should she set aside each mon

th to cover her renters insurance? $48
Mathematics
2 answers:
enyata [817]4 years ago
8 0
$96(2 payments) = $192

$192/(12 months) = $16 per month (she should set aside)
Natali [406]4 years ago
4 0

Answer: $16

Step-by-step explanation:

Given: Marie has renters insurance that she must pay twice a year.

The amount of each payment = $96

So, the total payment in the year = 2\times96=\$192

Since, in one year = 12 months

Therefore, the amount of money she should set aside each month to cover her renters insurance=\frac{192}{12}=16

Hence, She should set aside $16 each month to cover her renters insurance.

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f(x) = 10(10)+3 = 103 when x = 10

Step-by-step explanation:

Given a function piecewise as

f(x) = 2x-4 if -3<x<10

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We see from the definition of f(x) that the function has domain as (-3,13) and two sets defined from (-3,10) and [10,13).

Since 10 less than or equal to sign is there in the second function interval, we find that 10 is included in that.

Hence for finding f(10) we use the function defined for interval including 10 i.e. x^2+3

Substitute 10 for x in x^2+3

f(10) = 10^2+3

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Hence answer is 103

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