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JulsSmile [24]
3 years ago
9

Marie has renters insurance that she must pay twice a year. If each payment is $96, how much money should she set aside each mon

th to cover her renters insurance? $48
Mathematics
2 answers:
enyata [817]3 years ago
8 0
$96(2 payments) = $192

$192/(12 months) = $16 per month (she should set aside)
Natali [406]3 years ago
4 0

Answer: $16

Step-by-step explanation:

Given: Marie has renters insurance that she must pay twice a year.

The amount of each payment = $96

So, the total payment in the year = 2\times96=\$192

Since, in one year = 12 months

Therefore, the amount of money she should set aside each month to cover her renters insurance=\frac{192}{12}=16

Hence, She should set aside $16 each month to cover her renters insurance.

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A marketing researcher wants to find a 96% confidence interval for the mean amount those visitors spend per person per day while
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Answer:

n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38

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Step-by-step explanation:

Notation

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

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When we create a confidence interval for the mean the margin of error is given by this formula:

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And on this case we have that ME =4 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 96% of confidence interval now can be founded using the normal distribution. The significance is \alpha=1-0.96 =0.04. And in excel we can use this formula to find it:"=-NORM.INV(0.02;0;1)", and we got z_{\alpha/2}=2.054, replacing into formula (b) we got:

n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38

So then the minimum sample to ensure the condition given is n= 38

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