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JulsSmile [24]
3 years ago
9

Marie has renters insurance that she must pay twice a year. If each payment is $96, how much money should she set aside each mon

th to cover her renters insurance? $48
Mathematics
2 answers:
enyata [817]3 years ago
8 0
$96(2 payments) = $192

$192/(12 months) = $16 per month (she should set aside)
Natali [406]3 years ago
4 0

Answer: $16

Step-by-step explanation:

Given: Marie has renters insurance that she must pay twice a year.

The amount of each payment = $96

So, the total payment in the year = 2\times96=\$192

Since, in one year = 12 months

Therefore, the amount of money she should set aside each month to cover her renters insurance=\frac{192}{12}=16

Hence, She should set aside $16 each month to cover her renters insurance.

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A local company is concerned about the number of days missed by its employees due to ill ness. A Random Sample of 10 employees i
sukhopar [10]

Answer:

The incentive program does not cuts down on the number of days missed by employees.

Step-by-step explanation:

The dependent t-test (also known as the paired t-test or paired samples t-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.

A paired <em>t</em>-test would be used to determine whether the incentive program cuts down on the number of days missed by employees.

The hypothesis for the test can be defined as follows:

<em>H₀</em>: The incentive program does not cuts down on the number of days missed by employees, i.e. <em>d</em> ≥ 0.

<em>Hₐ</em>: The incentive program cuts down on the number of days missed by employees, i.e. <em>d</em> < 0.

From the information provided the data computed is as follows:

 n=10\\\bar d=-1.1\\SD_{d}=2.99

Compute the test statistic value as follows:

 t=\frac{\bar d}{SD_{d}/\sqrt{n}}

   =\frac{-1.1}{2.99/\sqrt{10}}\\\\=-1.16

The test statistic value is -1.16.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the p-value of the test as follows:

p-value=P(t_{n-1}

*Use a t-table.

The p-value of the test is 0.1379.

The p-value of the test is very large for all the commonly used significance level. The null hypothesis will not be rejected.

Thus, there is not enough evidence to support the claim.

Conclusion:

The incentive program does not cuts down on the number of days missed by employees

4 0
3 years ago
Can 11/100 be reduced?
kiruha [24]
No it can not be reduced

7 0
3 years ago
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Paige traveled to Australia and is making her favorite bread recipe. She usually bakes the bread in a 350F oven. She is surprise
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Answer:

Step-by-step explanation:

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3 years ago
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Fofino [41]

Answer:

Commutative Property

Step-by-step explanation:

Additive Identity: If you add a real number to zero or add zero to a real number, then you get the same real number back.

Additive Inverse: When you add the same number but reversed sign, you get 0.

Commutative Property: a + b = b + a

Addition distributive property: a(b+ c) = ab + ac.

In this case, we use the commutative property:

27 + 15 + 3 + 5 = 27 + 3 + 15 + 5.

We know that 27 + 3 = 30 and 15 + 5 = 20, so we get 50 quickly using mental math.

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Answer:

I believe it is y equals 3 minus 2x.

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