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DIA [1.3K]
3 years ago
10

What constant do you need to add to each of the following quadratic equations to complete the square?

Mathematics
1 answer:
Ghella [55]3 years ago
5 0
Where are the quadratic equations?
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A discount store bought two dozen cameras for $14 each.
____ [38]

Answer:

72.24

Step-by-step explanation:

Price for each camera = 14

Number of camera = 2dozen = 12 x 2 = 24

Total cp = 24 x 14 = 336

~~~~~~~~~~~~~~

Price for each camera=  10.99

Number of cams = 24

Total sp = 10.99 x 24 = 263.76

Loss = 336 - 263.76  = 72.24

6 0
2 years ago
Please help quickly !!!
kenny6666 [7]

Answer:

B) w^35

Step-by-step explanation:

you multiple the power of 5 by 7 to get 35

8 0
2 years ago
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What is the area of a circle whose diameter is 32 inches? Use π=3.14 in your calculations. Show your work.
Rina8888 [55]
R = 32 / 2 = 16
Pie = 3.14
Area of circle = pie x r^2
= 3.14 x 16^2 = 803.84
5 0
3 years ago
The atomic mass unit (amu) is a unit used to represent the blank of an atom.
aleksandrvk [35]

Answer:

the answer is no

Step-by-step explanation:

5 0
3 years ago
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An art project has an area of 63.6 square inches. What is the width, in inches, of the project?
Flura [38]

Answer:

The width of the art projects of area 63.6 square inches is 7.97 inches .

Step-by-step explanation:

Given as :

The area of the square art project = 63.6 square inches

Since The shape of the art project is square

So, The Area of square = A = side × side = side²

Now, let the measure of the width of art project = w inches

I.e side = w inches

or ,  A  = side²

Or , A = w²

Or, 63.6 = w²

So, w = \sqrt{63.6}

I.e w = 7.97 inches

So, the width of the projects = w = 7.97 inches

Hence The width of the art projects of area 63.6 square inches is 7.97 inches . Answer

4 0
3 years ago
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