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DIA [1.3K]
3 years ago
10

What constant do you need to add to each of the following quadratic equations to complete the square?

Mathematics
1 answer:
Ghella [55]3 years ago
5 0
Where are the quadratic equations?
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You are making luan arrangements for a birthday party. There are 16 white balloons and 24 red balloons each arrangement must be
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Answer:

8 arrangement

Step-by-step explanation:

2 white balloons and 3 red balloons for every arrangement

5 0
3 years ago
HELP ASAP PLZ !! 15 POINTS !!
Ket [755]

the first answer common ratio is t2/t1=32/16

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8 0
3 years ago
Kalani had 3/5 pan of brownies. She sent 1/3 of
frozen [14]

I think its.......5/15=1/3

8 0
3 years ago
4(3x^2y^4)^3 / (2x^3y^5)^4
tatyana61 [14]

Solving the expressions  \frac{4(3x^2y^4)^3}{(2x^3y^5)^4} we get \frac{27}{4x^{6}y^{8}}

Step-by-step explanation:

We need to Solve the expression: \frac{4(3x^2y^4)^3}{(2x^3y^5)^4}

Solving:

\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}

=\frac{4(3^3x^6y^{12})}{(2^4x^{12}y^{20})}\\=\frac{4(27x^6y^{12})}{(16x^{12}y^{20})}\\=\frac{108x^6y^{12}}{16x^{12}y^{20}}

Applying exponent rule: \frac{x^a}{x^b}=x^{a-b}

=\frac{108x^{6-12}y^{12-20}}{16}\\=\frac{27x^{-6}y^{-8}}{4}

Another exponent rule says: x^{-a}=\frac{1}{x^a}=

=\frac{27}{4x^{6}y^{8}}

So, solving the expressions  \frac{4(3x^2y^4)^3}{(2x^3y^5)^4} we get \frac{27}{4x^{6}y^{8}}

Keywords: Solving Exponents  

Learn more about Solving Exponents at:

  • brainly.com/question/13174260
  • brainly.com/question/13174254
  • brainly.com/question/13174259

#learnwithBrainly

8 0
3 years ago
carol bought 8 identical boxes for a total of 3.60$. how much did each box cost? which statement would you use?
Tju [1.3M]
You just divide the 3.60 by the eight and then you get 45 cents for each box.
7 0
3 years ago
Read 2 more answers
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