Answer:
![\left[\begin{array}{cc}0&-1\\-1&0\\-1&-1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0%26-1%5C%5C-1%260%5C%5C-1%26-1%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
In this question we have to subtract the corresponding entries of column of matrix 1 and the matrix 2 corresponding entries
![=\left[\begin{array}{cc}-1&0\\1&-2\\1&3\end{array}\right]-\left[\begin{array}{cc}-1&1\\2&-2\\2&4\end{array}\right] \\=\left[\begin{array}{cc}-1-(-1)&0-1\\1-2&-2-(-2)\\1-2&3-4\end{array}\right]\\=\left[\begin{array}{cc}-1+1&-1\\-1&-2+2\\-1&-1\end{array}\right]\\=\left[\begin{array}{cc}0&-1\\-1&0\\-1&-1\end{array}\right]](https://tex.z-dn.net/?f=%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1%260%5C%5C1%26-2%5C%5C1%263%5Cend%7Barray%7D%5Cright%5D-%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1%261%5C%5C2%26-2%5C%5C2%264%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1-%28-1%29%260-1%5C%5C1-2%26-2-%28-2%29%5C%5C1-2%263-4%5Cend%7Barray%7D%5Cright%5D%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1%2B1%26-1%5C%5C-1%26-2%2B2%5C%5C-1%26-1%5Cend%7Barray%7D%5Cright%5D%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0%26-1%5C%5C-1%260%5C%5C-1%26-1%5Cend%7Barray%7D%5Cright%5D)
Complete question :
There are 575 fireworks to be shot off in a firework display every minute 12 new fireworks are shot off display write a verbal model and algebraic expression to represent the number of fireworks left to be shot off after t minutes.
Answer:
575 - 12t
Step-by-step explanation:
Given the following :
Total number of fireworks = 575
Number of shots per minute = 12
To calculate the number of fireworks left to be shot off after t minutes, The total number of fireworks already shot after the same time interval t in minutes, is first obtained, this is equivalent to (12*t). The result is then subtracted from the total number of fireworks to be shof off.
In algebraic terms
[total number of fireworks on display - (number of shots per minute × t)]
575 - 12t
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Answer:
2.50 dollars.
Step-by-step explanation:
Given:
Will and his friends buy a large salad to share and several slices of pizza, p.
The graph given shows the total cost for lunch, c and slices of pizza,p.
p is marked horizontally, and c vertically.
Observing the points marked we find that for every increase of one slice of pizza, the cost i.e. c on vertical line increases by 0.50 times vertical grid.
Since each grid equals 5 dollars vertically, we find 1/2 grid increase is equal to increase of 1/2(5 ) =2.50 dollars.
Thus for increase of one slice of pizza, 2.50 dollars cost is increased.
