Answer:
-2, 3, -0.5 + 0.866i, -0.5 - 0.866i.
Step-by-step explanation:
As the last term is -6 , +/- 2 , +/- 3 are possible zeroes.
Try 2:-
(2)^4 - 6(2)^2 - 7(2) - 6 = -28 so 2 is not a zero.
3:-
(3)^4 - 6(3)^2 - 7(3) - 6 = 0 so 3 is a zero.
(-2)^4 - 6(-2)^2 - 7(-2) - 6 = 0 so -2 is also a zero.
Divide the function by (x +2)(x - 3), that is x^2 - x - 6
gives x^2 + x + 1
x^2 + x + 1
So we have x^2 + x + 1 = 0
x = [-1 +/- √(1^1 - 4*1*1)] / 2
= -1 + √(-3) / 2 , - 1 - √(-3) / 2.
= -0.5 + 0.866i, -0.5 - 0.866i
Answer:
48in sq
Step-by-step explanation:
8*12/2=8*6=48
Answer:
3 Because there are only three bells that aren't being run there for three additional ways that the bells could be rung
So elimination method is basically adding the equations and canceling out variables.
-6x + 6y = 6
-6x + 3y = -12
The eaiest way to solve is by multiplying the bottom equation by -1.
-6x + 6y = 6
6x - 3y = 12
Now you add the eqautions.
3y = 18
Divde 3 from both sides.
y = 6
Now plug in 6 into any of the original two equations. Lets use the first one.
-6x + 6(6) = 6
-6x + 36 = 6
Subtract 36 from both sides.
-6x = -30
Divide -6 from both sides.
x = 5
So your solution is (5, 6).
I hope this helps love! :)
0.362 in expanded form is 0.3 + 0.06 + 0.002
