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2 years ago

What does "when x is an integer" mean?

Mathematics

1 answer:

MariettaO [177]2 years ago

8 0

Answer:

x = whole-valued numbers without fractions or decimal.

Step-by-step explanation:

An integer in mathematics refers to a whole number that can either be a positive or negative number but without any fractional part. Integers are numbers such as -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5 etc.

Hence, when we say "x" is an integer, it simply means that the value of x should be a whole number that can either be a positive or negative number but without any fractional or decimal value or part.

In Mathematics, when solving for an unspecified or unknown integer we can use a lowercase alphabet "x" to denote the integer.

For instance;

2x + 5 = 11

2x = 11 - 5

2x = 6

Dividing both sides by 2, we have;

x = 3.

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U − -23 _______ = -8 -9 Solve for u Thanks!

Romashka [77]

Answer:

u=95

Step-by-step explanation:

To solve this problem we need to isolate 'u' variable using properties of equation.

Lets multiply by -9 the whole equation

u - -23=-8*9

Remember keys features of algebra:

- * - = +

- * += -

+ * - = -

+ * + =+

So, our equations becomes>

u+23=-72

Lets now subtract 23 to both sides

u-23=-72-23

We have u=95

8 0

2 years ago

Read 2 more answers

The nth term of a sequence is n2 + 4

Westkost [7]

1 is an odd number so let’s put 1 into n, (1)2+4 which equals 2+4 which is 6, 6 is not a prime number as it can has factors such as 2&3 not just 1&6.

5 0

2 years ago

Answer needed quick is it supplementary vertical complementary adjacent

Archy [21]

Hey!!

They are adjacent angles.

Both angles have common side and vertex.

Hope it will help u...

8 0

3 years ago

Read 2 more answers

assume that when adults with smartphones are randomly selected 15 use them in meetings or classes if 15 adult smartphones are ra

Tanzania [10]

Answer:

The probability that at least 4 of them use their smartphones is 0.1773.

Step-by-step explanation:

We are given that when adults with smartphones are randomly selected 15% use them in meetings or classes.

Also, 15 adult smartphones are randomly selected.

Let X = Number of adults who use their smartphones

The above situation can be represented through the binomial distribution;

$P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; n = 0,1,2,3,.......$

where, n = number of trials (samples) taken = 15 adult smartphones

r = number of success = at least 4

p = probability of success which in our question is the % of adults

who use them in meetings or classes, i.e. 15%.

So, X ~ Binom(n = 15, p = 0.15)

Now, the probability that at least 4 of them use their smartphones is given by = P(X $\geq$ 4)

P(X $\geq$ 4) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

= $1- \binom{15}{0}\times 0.15^{0} \times (1-0.15)^{15-0}-\binom{15}{1}\times 0.15^{1} \times (1-0.15)^{15-1}-\binom{15}{2}\times 0.15^{2} \times (1-0.15)^{15-2}-\binom{15}{3}\times 0.15^{3} \times (1-0.15)^{15-3}$

= $1- (1\times 1\times 0.85^{15})-(15\times 0.15^{1} \times 0.85^{14})-(105 \times 0.15^{2} \times 0.85^{13})-(455 \times 0.15^{3} \times 0.85^{12})$

= 0.1773

3 0

3 years ago

1- (-6k + 6) < 3k +1 + 5k

rjkz [21]

Answer:

k>5/14

Step-by-step explanation:

4 0

3 years ago