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Tema [17]
3 years ago
9

Caleb drives for 3 hours at 15 mph how far does he travel

Mathematics
1 answer:
Valentin [98]3 years ago
6 0
Caleb travels at 45 mph
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Expand and simplify (2x−12)^2. Is this a special product?
Rom4ik [11]

Answer:

Step-by-step explanation:

(2x−12)^2 can be factored into 2^2*(x - 6)^2, which in turn becomes

4(x^2 - 12x + 36).  Yes, this is a special product of the form

(a - b)^2 = a^2 - 2ab + b^2.

8 0
2 years ago
What is the domain? y= -3x2+4x–6
yuradex [85]

Answer:

All real numbers.

Step-by-step explanation:

In this equation, x can stretch across the graph.

5 0
3 years ago
Read 2 more answers
6m+12 = 2(2m+8) I need help
Paul [167]
6m+12 = 4m+16
2m = 4
m=2
3 0
3 years ago
Read 2 more answers
MZJ = _<br>MZK =<br>mZL =<br>24 cm​
Bezzdna [24]

Answer:

can we get a bit more information

6 0
3 years ago
Which of the following best explains why
Dima020 [189]

We can see values of angles in degrees first

\frac{5\pi}{6}   = \frac{5 \times 180}{6}= \frac{900}{6} = 150°

Similarly

\frac{5\pi}{3}   = \frac{5 \times 180}{3}= \frac{900}{3} = 300°

Now reference angle means positive acute angle they will have

As we can see in attachment 150° lies in second quadrant so its reference angle will be 180°-150° = 30° from x axis line as shown.

Where as angle 300° lies in fourth quadrant so its reference angle will be 360° - 300° = 60° from x axis as shown. So clearly both reference angles are different . So 1st choice " angles donot have same reference angle" best explains it

Choice (2) and (3) are incorrect as tan is positive only in first and third quadrants and angle 300° is in fourth quadrant.

since angle 150° is in second quadrant and 300° is in fourth quadrant so both will have same negative sign so choice (4) is not correct.

So final ansewr is choice (1) "the angles donot have same reference angle"

8 0
3 years ago
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