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Molodets [167]
3 years ago
13

The number of patients treated at Dr. Artin’s dentist office each day was recorded for nine days. These are the data: 6, 6, 6, 5

, 5, 6, 5, 6, 5. Find the mean, median, mode, and range of the data. If necessary, round to the nearest tenth.
Mathematics
1 answer:
Sholpan [36]3 years ago
5 0
Mean is all the numbers added divided my the number of numbers
6+6+6+5+5+6+5+6+5/9
5.55
median is the middle number
6
mode is the number that occurs the most
6
Range is the maximum minus the minimum
6-5
1
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What is the area of this figure?
Paraphin [41]
Area of square
= 7x7
=49
Area of triangle
=0.5x 7x12
=42
Total area of figure
=49+42
=91

Hence, answer is D
6 0
4 years ago
Hiroto spends \$68 on e-books and paperback books combined. Each e-book he buys costs $5 and each paperback book he buys costs $
alina1380 [7]

The equation that can be used to model the situation regarding the e-books and paperback is 5x + 12y = 68

The following information can be gotten from the question:

Total amount spent on e-books and paperback = $68

<em>Cost</em><em> of e-book = $5 each.</em>

<em>Cost of paperback = $12 each</em>

<em>Number of</em><em> e-books</em><em> = x</em>

<em>Number of paperbacks = y</em>

Therefore, the equation that can be used to model the situation regarding the <em>e-books </em>and <em>paperback</em> will be:

= 5(x) + 12(y) = 68

5x + 12y = 68

The equation will be 5x + 12y = 68

Read related link on:

brainly.com/question/25212173

5 0
2 years ago
Select the equivalent expression. <br><br> A, B or C?
Alina [70]

Answer:

  A

Step-by-step explanation:

The relevant rules of exponents are ...

  (a^b)^c = a^(bc)

  a^-b = 1/a^b

__

  \left(\dfrac{2^{-10}}{4^2}\right)^7=\dfrac{2^{(-10)(7)}}{4^{(2)(7)}}=\dfrac{2^{-70}}{4^{14}}\\\\=\boxed{\dfrac{1}{2^{70}\cdot 4^{14}}}

6 0
4 years ago
Rewrite terms that are subtracted as addition of the opposite. g2 + (–4g4) + 5g + 9 + (–3g3) + 3g2 + (–6) Group like terms. Comb
Vilka [71]

Answer:

-4g^4 -3g^3 + 4g^2 +5g +3

Step-by-step explanation:

g^2 + -4g^4 +5g +9 -3g^3 + 3g^2 -6

-4g^4 -3g^3 + 4g^2 +5g +3

3 0
4 years ago
La familia Sánchez Olguín, quiere terminar de construir su casa y necesita S/.25000 para todos los gastos del acabado de la casa
erastova [34]

Extraemos los datos del problema:

  • Capital Inicial → C₀ = S/.25000
  • Interés bimestral → i = 8 % = 0.08
  • Periodos →  n = 3
<h2 /><h2>Bimestre 1:</h2>

Capital Inicial Bimestre → C = S/.25000

Tasa de interés bimestral:

I = C×i

I = S/.25000 × 0.08

I = S/.2000

Monto final:

M = C + I

M = S/.25000 + S/.2000

M = S/.27000

Variación Porcentual:

% = (M - C₀) / C₀

% = ( 27000 - 25000) /  25000

% = 8

<h2>Bimestre 2:</h2>

Capital Inicial Bimestre → C = S/.27000

Tasa de interés bimestral:

I = C×i

I = S/.27000 × 0.08

I = S/.2160

Monto final:

M = C + I

M = S/.27000 + S/.2160

M = S/.29160

Variación Porcentual:

% = (M - C₀) / C₀

% = ( 29160 - 25000) /  25000

% = 16.64

<h2>Bimestre 3:</h2>

Capital Inicial Bimestre → C = S/.29160

Tasa de interés bimestral:

I = C×i

I = S/.29160 × 0.08

I = S/.2332.8

Monto final:

M = C + I

M = S/.29160 + S/.2332.8

M = S/ 31492.8

Variación Porcentual:

% = (M - C₀) / C₀

% = ( 31492.8 - 25000) /  25000

% = 25.97

7 0
3 years ago
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