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Natasha2012 [34]
3 years ago
13

Help help , Please help! Brainliest if correct! What was the equation of the graph below before it was shifted to the left 1.5 u

nits? A. G(x)=(x3)^3-(x-3) B. G(x)=(x-1.5)^3 C. G(x)=(x)^3 D.G(x)=x^3-x

Mathematics
1 answer:
patriot [66]3 years ago
7 0

Answer:

Option (D). G(x) = x³ - x

Step-by-step explanation:

Given function is the attachment,

G(x) = (x - 1.5)³ - (x - 1.5)

This function when translated by left by 1.5 units, rule for the translation is,

G(x) → G'(x + 1.5)

Therefore, translated function will be,

G'(x) = (x - 1.5 + 1.5)³ - (x - 1.5 + 1.5)

G'(x) = x³ - x

Therefore, Option (D) will be the answer.

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Determine which equations have the same solution set as StartFraction 2 Over 3 EndFraction minus x plus StartFraction 1 Over 6 E
Lina20 [59]

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A, B, F

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2/3 - x + 1/6 = 6x

Collect like terms

2/3 + 1/6 = 6x + x

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= 5/6 × 1/7

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a) 4 - 6x + 1 = 36x

4 + 1 = 36x + 6x

5 = 42x

x = 5/42

Equivalent to the last step of the simplification above

b) 5/6 - x = 6x

5/6 = 6x + x

5/6 = 7x

This is equivalent to the third step of the simplification

c) 4 - x + 1 = 6x

4 + 1 = 6x + x

5 = 7x

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Not equivalent to any of the steps in the simplification above

d) 5/6 + x = 6x

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x = 5/6 ÷ 5

= 5/6 × 1/5

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Not equivalent to any of the steps in the simplification above

e) 5 = 30x

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Not equivalent to any of the steps in the simplification above

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4 0
3 years ago
Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form?
Sergeu [11.5K]
Hello!

First of all we find the slope by dividing the difference of the y values by the difference of the x values as seen below.

\frac{-3-11}{1+3} = -\frac{14}{4} = \frac{7}{2}

The slope of our line is 7/2, or 3.5
-------------------------------------------------------------
Now we will put the slope and a point on our line into slope intercept form and solve for b. We will use (-3,11).

11=3.5(-3)+b
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Our final equation is shown below.

y=3.5x+0.5

I hope this helps!


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