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vitfil [10]
3 years ago
8

5x+7y=10 8x-5y=2 Please help!

Mathematics
1 answer:
Mrrafil [7]3 years ago
5 0
(x,y)=(64/81, 70/81) I can provide a description if needed. I used the process of elimination. 
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A quadratic equation ax^2+bx+c=0 has -11 and 4 as solutions. Find the values of b and c if the value of a is 1 (hint, use zero f
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Answer:

b = 7, c = -44

Step-by-step explanation:

If the quadratic equation has the solutions -11 and 4, the two factors are:

(x+11)(x-4)=0

Since when we use the zero factor property we get

x+11=0 ⇒ x= -11

x-4=0 ⇒  x=4

Thus, we have used the zero factor property in reverse to find the factorization of the quadratic equation.

Now we develop the multiplications between parenthesis:

(x+11)(x-4)=0\\x^2-4x+11x-44=0\\x^2+7x-44=0

So b is the number that accompanies the x: b = 7

and c is the independent number: c = -44

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3 years ago
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4 years ago
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3 years ago
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Answer:

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