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1 year ago

What is the simplest form of ^4sqrt324x^6y^8

Mathematics

1 answer:

svetlana [45]1 year ago

3 0

$\rm{\green{Answer \: is:-}}$

$3xy \sqrt[24]{ {4x}^{2} }$ (3xy^2 4 sqrt 4x^2)

Step-by-step explanation:

<h3>Hope it's helpful to you</h3>

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What times itself 3 times to get -0.125

Verdich [7]

That would be -0.041

-0.125/3 = -0.041666666

5 0

2 years ago

Chris is reading a book that has nine-hundred seventy-eight pages in it. Every night

GaryK [48]

9514 1404 393

Answer:

Every night

Step-by-step explanation:

The problem statement tells you ...

"Every night Chris reads a number of pages that can be rounded to the nearest hundred."

Then it asks you ...

"On what nights does Chris read a number of pages that can be rounded to the nearest hundred?"

If we take the problem statement at face value, the answer must be ...

"Every night."

7 0

2 years ago

-5(9 - 6k) with k = -3

Jobisdone [24]

Answer:

-135

Step-by-step explanation:

-5(9 - 6k)

Let k = -3

-5 ( 9 - 6*-3)

-5 ( 9 + 18)

-5 ( 27)

3 0

2 years ago

Find the distance between the points (-3,2) and (4,-5)

alexandr1967 [171]

You have to use the distance formula. sqrt((x2-x1)^2+(y2-y1)^2) So sqrt((4+3)^2+(-5-2)^2). sqrt(49+49). Sqrt(98). 9.89

6 0

3 years ago

The town of Hayward (CA) has about 50,000 registered voters. A political research firm takes a simple random sample of 500 of th

Ilia_Sergeevich [38]

Answer:

(0.0757;0.1403)

Step-by-step explanation:

1) Data given and notation

Republicans =115

Democrats=331

Independents=54

Total= n= 115+331+54=500

$\hat p_{ind}=\frac{54}{500}=0.108$

Confidence=0.98=98%

2) Formula to use

The population proportion have the following distribution

$\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the population proportion is given by this formula

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

We have the proportion of independents calculated

$\hat p_{ind}=\frac{54}{500}=0.108$

We can calculate $\alpha=1-conf=1-0.98=0.02$

And we can find $\alpha/2 =0.02/2=0.01$ , with this value we can find the critical value $z_{\alpha/2}$ using the normal distribution table, excel or a calculator.

On this case $z_{\alpha/2}=2.326$

3) Calculating the interval

And now we can calculate the interval:

$0.108 - 2.326\sqrt{\frac{0.108(1-0.108)}{500}}=0.0757$

$0.108 + 2.326\sqrt{\frac{0.108(1-0.108)}{500}}=0.1403$

So the 98% confidence interval for this case would be:

(0.0757;0.1403)

7 0

2 years ago