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2 years ago

What is the simplest form of ^4sqrt324x^6y^8

Mathematics

1 answer:

svetlana [45]2 years ago

3 0

$\rm{\green{Answer \: is:-}}$

$3xy \sqrt[24]{ {4x}^{2} }$ (3xy^2 4 sqrt 4x^2)

Step-by-step explanation:

<h3>Hope it's helpful to you</h3>

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Who knows how to do this I TRULY NEED HELP

grigory [225]

It’s 59°
cause 74+47=121
180-121=59

3 0

3 years ago

After a new product is launched the cumulative sales S(t) (in $1000) t weeks after launch is given by:

LenaWriter [7]

Answer:

$17.750 ; 15.979 ; 72

Step-by-step explanation:

Given that :

Cummulative sales, S(t) is represented by the equation :

S(t) = 72/(1 + 9e^-0.36t)

Cummulative sales after 3 weeks :

Put t = 3 in the equation, as t = time after launch

S(3) = 72/(1 + 9e^-0.36(3))

S(3) = 72 / (1 + 9e^-1.08)

S(3) = 72 / (1 +3.0563597)

S(3) = 72 / 4.0563597

S(3) = 17.749905 = $17.750 thousands

Amount of time required for sales to reach 70000

S(t) = 72/(1 + 9e^-0.36t)

S(t) = 70

70 = 72/(1 + 9e^-0.36t)

70 * (1 + 9e^-0.36t) = 72

(1 + 9e^-0.36t) = 72 / 70

1 + 9e^-0.36t = 1.0285714

9e^-0.36t = 1.0285714 - 1

9e^-0.36t = 0.0285714

e^-0.36t = 0.0285714 / 9

e^-0.36t = 0.0031746

Take the In of both sides ;

In(e^-0.36t) = In(0.0031746)

-0.36t = - 5.752573

t = - 5.752573 / - 0.36

t = 15.979

About 16 weeks

The limiting value in sales :

Take the limit as t - - > ∞

S(t - - > ∞) = 72/(1 + 9e^-0.36t)

Put t = 0

S(0) - - > 72 / (1 + 0)

72 / 1

= 72

8 0

2 years ago

Pls help me I need this now pls

LenaWriter [7]

Answer:

450 cm

Step-by-step explanation:

25 on both sides 2x25

4 squares = 25x4

4 sides for 4 squares = 100x4

400+50

4 0

3 years ago

Read 2 more answers

Find the surface area of a cylinder with a base diameter of 8 yd and a height of 8 yd. Use the value 3.14 for , and do not do an

GuDViN [60]

Answer:

A=301.59 yd2

Step-by-step explanation:

A=2πrh+2πr2

Thats the formula

7 0

3 years ago

A high school mathematics teacher can grade a set of exams in 7 hours working alone. If their student teacher helps them, it wi

Stels [109]

It takes 9 hrs 19.8 minutes for the student teacher to grade the exams if they worked alone

<u>Solution:</u>

Let the efficiency of the school teacher be “x” and the efficiency of the student teacher be “y”

Here the word efficiency means the rate of doing work

Let the total work to be completed be W

According to the question,

The time taken by the school teacher to complete the work is 7 hrs.

So we can write it in equation form

$W = x \times 7$ ---- eqn 1

where W is the total work and x is the efficiency

Similarly for student teacher and school teacher doing the work simultaneously, we can write the equation as

$W =(x +y ) \times 4$

Equating eqn 1 and 2

$x \times 7=(x+y) \times 4$

7x = 4x + 4y

3x = 4y

So in ratio x : y = 4 : 3

Now putting value of x = 4 in equation (1) we get total work to be 28

Now, <em>total time taken by the student teacher = total work ÷ efficiency of student teacher</em>

Hence, total time taken by the student teacher = 28 ÷ 3 = 9.33 hrs

= 9 hrs 19.8 minutes

Hence it takes 9 hrs 19.8 minutes for the student teacher to grade the exams if they worked alone

4 0

3 years ago