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jeyben [28]
3 years ago
9

Please help!!!! Tell me whether it’s a equation or not pleasr

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
3 0
This answer is a equation, my teacher told me this
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GEOMETRY PLEASE HELP
marysya [2.9K]

Answer:

see explanation

Step-by-step explanation:

(5)

Since ∠EBA = 90° then ∠ABD = 90° ( straight angle ) and

∠ABC + ∠CBD = ∠ABD, that is

2x + 3x - 10 = 90, simplifying

5x - 10 = 90 ( add 10 to both sides )

5x = 100 ( divide both sides by 5 )

x = 20, thus

∠ABC = 2x = 2 × 20 = 40°

∠CBD = 3x - 10 = (3 × 20) - 10 = 60 - 10 = 50°

(6)

4x - 18 = 3x + 7 ( vertical angles are congruent )

Subtract 3x from both sides

x - 18 = 7 ( add 18 to both sides )

x = 25

7y = 5y + 28 ( vertical angles are congruent )

Subtract 5y from both sides

2y = 28 ( divide both sides by 2 )

y = 14

7 0
3 years ago
I need help with this problem quick.
KatRina [158]

The absolute value - or distance from zero, is fairly simple to find. Make your final answer positive to find it.


|\frac{10-7}{4}| = |\frac{3}{4}| = |.75| = .75

|\frac{-15+8}{6}| = |-\frac{7}{6}| = |-1.2| = 1.2

8 0
3 years ago
Henri bought a swim suit at a cost of $8. Which statements are true regarding the cost of the suit? Select three options
uysha [10]

Answer:

where are the options

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
If you add the digits in a two-digit number and multiply the sum by 7, you get the original number. If you reverse the digits in
kolbaska11 [484]
The answer is A. 42

Solution:
Let x= ones digit, y=tens digit

1st condition (original number) : 7(x+y)=10y + x
2nd condition (new number by reversing the digits): 18+x+y=10x+y

simplifying:
1st condition: 6x=3y
2nd condition: x=2
substituting x=2 to 6x=3y
<span>y=4</span>
3 0
3 years ago
Read 2 more answers
Consider the following statement: The square of a prime number is not prime. (a) Write this as an if-then statement, using caref
Hitman42 [59]

The square of a prime number is not prime.

a) let x ∈ R, If x  ∈ {prime numbers}, then x^{2}∉{prime numbers}

there says that if x is a real and x is in the set of the prime numbers, then the square of x isn't in the set of prime numbers.

b) Prove or disprove the statement.

ok, if x is a prime number, then x only can be divided by himself. Now is easy to see that x^{2} = x*x can be divided by himself and x, then x*x is not a prime number, because can be divided by another number different than himself

7 0
3 years ago
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