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melomori [17]
3 years ago
12

17,22,36,55,61,79 what is the median

Mathematics
2 answers:
Lunna [17]3 years ago
6 0

Median is the middle number. To find median, the numbers must be ordered from least to greatest. The numbers are already ordered.

17,22,36,55,61,79

The middle numbers are 36 and 55, with 2 numbers on each side.

a, b, c, d, e, f

Add the 2 numbers and divide by 2

36 + 55 = 91

Now divide by 2

91 \div 2 = 45.5

The median is 45.5

Firdavs [7]3 years ago
4 0
The median should be 45.5 because when u find 2 median numbers (aka 36 and 55) then that means you have to add both median and then divide it by 2 which gives you 45.5 as the median
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<h2>The Pythagorean Theorem</h2>

The Pythagorean Theorem: a^2+b^2=c^2

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  • <em>c</em> is the hypotenuse (the longest side of a right triangle; opposite the 90° angle
  • <em>*keep in mind that this theorem applies only to right triangles</em>

<h2>Solving the Question</h2>

We're given:

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Plug these measurements into the Pythagorean theorem:

a^2+b^2=c^2\\9^2+12^2=c^2

⇒ Combine like terms:

81+144=c^2\\c^2=225

<h2>Answer</h2>

c^2=225

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Answer:

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A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

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The confidence interval for the mean is given by the following formula:  

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:  

df=n-1=47-1=46  

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,46)".And we see that t_{\alpha/2}=2.01  

Now we have everything in order to replace into formula (1):  

525-2.01\frac{75}{\sqrt{47}}=503.01  

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So on this case the 95% confidence interval would be given by (503.01;546.99)

Part b

The margin of error is given by this formula:  

ME=t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

And on this case we have that ME =7 msec, we are interested in order to find the value of n, if we solve n from equation (1) we got:  

n=(\frac{t_{\alpha/2} s}{ME})^2 (2)  

The critical value for 95% of confidence interval is provided, t_{\alpha/2}=2.01 from part a, replacing into formula (2) we got:  

n=(\frac{2.01(75)}{7})^2 =463.79 \approx 464  

So the answer for this case would be n=464 rounded up to the nearest integer  

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