Answer:
The amount of sales in order to cover his monthly expenses must be greater than or equal to $22,500
Step-by-step explanation:
Let
x----> represent the amount of sales Ollie will need
we know that
The amount of sales for the month multiplied by the commission rate as a decimal plus the fixed amount must be greater than or equal to $5,400 each month
so
The inequality that represent this situation is
solve for x
subtract 2,700 both sides
divide by 0.12 both sides
The amount of sales in order to cover his monthly expenses must be greater than or equal to $22,500
Step-by-step explanation:
- P = 2 (2x+7) + 2(3x +4)
- Now, comparing the above with 62 we get x=4
- Length is 16 and width is 15
Answer:
27
Step-by-step explanation:
-21/-7 =3 so x is 3y. if you plug 9 in for y you get 3(9) then you multiply and get 27.
Answer:
Step-by-step explanation:
Since the incubation times are approximately normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = incubation times of fertilized eggs in days
µ = mean incubation time
σ = standard deviation
From the information given,
µ = 19 days
σ = 1 day
a) For the 20th percentile for incubation times, it means that 20% of the incubation times are below or even equal to 19 days(on the left side). We would determine the z score corresponding to 20%(20/100 = 0.2)
Looking at the normal distribution table, the z score corresponding to the probability value is - 0.84
Therefore,
- 0.84 = (x - 19)/1
x = - 0.84 + 19 = 18.16
b) for the incubation times that make up the middle 97% of fertilized eggs, the probability is 97% that the incubation times lie below and above 19 days. Thus, we would determine 2 z values. From the normal distribution table, the two z values corresponding to 0.97 are
1.89 and - 1.89
For z = 1.89,
1.89 = (x - 19)/1
x = 1.89 + 19 = 20.89 days
For z = - 1.89,
- 1.89 = (x - 19)/1
x = - 1.89 + 19 = 17.11 days
the incubation times that make up the middle 97% of fertilized eggs are
17.11 days and 20.89 days
