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BigorU [14]
2 years ago
7

5 5/7 divided by 1 3/5 • 4 2/3

Mathematics
1 answer:
Ipatiy [6.2K]2 years ago
8 0

Answer:2 /34 divided by 2 1/5

= 2/34 ÷ 11/5

=5/34

Step-by-step explanation:

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What number is 3.4 more than 7.3?
Westkost [7]

Answer:

10.7

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
In the figure, AB is parallel to CD, XY is the perpendicular bisector of AB, and E is the midpoint of XY. Prove that △AEB ≅ △DEC
Makovka662 [10]

Answer:

From top to bottom:

A, J, E, B, I, C, D, G, F, H

See below for more clarification.

Step-by-step explanation:

We are given that AB is parallel to CD, XY is the perpendicular bisector of AB, and E is the midpoint of XY. And we want to prove that ΔAEB ≅ ΔDEC.

Statements:

1) XY is perpendicular to AB.

Definition of perpendicular bisector.

2) XY ⊥ CD.

In a plane, if a transveral is perpendicular to one of the two parallel lines, then it is perpendicular to the other.

3) m∠AXE = 90°, m∠DYE = 90°.

Definition of perpendicular lines.

4) ∠AXE ≅ ∠DYE.

Right angles are congruent.

5) XE ≅ YE

Definition of a midpoint.

6) ∠A ≅ ∠D.

Alternate Interior Angles Theorem

7) ΔAEX ≅ ΔDEY

AAS Triangle Congruence*

(*∠A ≅ ∠D, ∠AXE ≅ ∠DYE, and XE ≅ YE)

8) AE ≅ DE

Corresponding parts of congruent triangles are congruent (CPCTC).

9) ∠AEB ≅ ∠DEC

Vertical Angles Theorem

10) ΔAEB ≅ ΔDEC

ASA Triangle Congruence**

(**∠A ≅ ∠D, AE ≅ DE, and ∠AEB ≅ ∠DEC)

3 0
3 years ago
What is 42/70 x 20/22
rusak2 [61]

Answer:

6/11 or 0.545

6 0
2 years ago
luke jogged a total of 56.5 miles last week. if luke jogged the same distance,d, each day for 3 days and half that distance on e
Leokris [45]
The algebraic equation used to answer this question is:
3d + 4(1/2d) = 56.5
This is because he ran d, the distance, three times that week. For the rest of the four days, he ran 1/2 the distance, or half d.
To find the answer, you first distribute:
3d + 2d = 56.5
Add like terms:
5d = 56.5
Divide both side by 5:
5d/5 = 56.5/5
d = 11.3
On the first three days, Luke jogged 11.3 miles. On the remaining days, where he jogged 1/2d, Luke jogged 5.65 miles.
Hope this helps!
3 0
3 years ago
Yats of fle har earh par<br> O2 yr<br> 03 ya<br> 04yads<br> 111
Marianna [84]

Answer:huh?

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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