Let the total no. of 25 p coins be x
50p coins = 2x
Value of 25 p coins ( in rupees) = 0.25*x =0.25x
Value of 50p coins ( in rupees) = 0.5*2x = x
0.25x+x = 25
1.25x =25
x = 25/1.25 = 20
no. if 25p coins = 20
and 50p coins = 2*20 = 40
9/10,
3/4 = 15/20
9/10 = 18/20
Clearly 9/10 is greater.
Answer:
46
Step-by-step explanation:
Let represent a number with in the ten's position and is the one's position.
This means actually has value of .
We are given the sum of those digits of is 10; this means .
It says if 18 is added to the number , then the result is .
So has value and
has value .
We are given then:
Subtract on both sides:
Simplify:
Subtract on both sides:
Divide both sides by 9:
Rearrange by commutative property:
So the system of equations we want to solve is:
-------------------------Add equations together (this will eliminate the variable and allow you to go ahead and solve for :
Divide both sides by 2:
Simplify:
If and , then . since 4+6=10.
So the original number is (46).
18 more than 46 is 18+46=(64) which is what we wanted.
We also have the sum of 4 and 6 is 10 as well.
The answer to your question would be D.
there is no way to tell if any of the other options are true or not so the only possible choice would be D.
Hope this helps! :)