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maksim [4K]
4 years ago
11

Why is m step so hard??

Mathematics
1 answer:
frosja888 [35]4 years ago
7 0
Explain more , so i can help
You might be interested in
The sum of two integers is -8.if one integer is 12 then the other is?
jeka57 [31]

Answer:

2 and -10

Step-by-step explanation:

let the two integers be x and y.

so, x+y=-8---‐-------(1)

and,

x=y+12-------‐-----(2)

from (1) and (2),

(y+12)+y=-8

or, 2y=-8-12

or, y=-20/2

or, y=-10

substitutting the value of y in (2),

x=-10+12=2

therefore the required integers are 2 and -10.

3 0
3 years ago
Read 2 more answers
A 2-pack of jump ropes costs $1.80. What is the unit price?<br><br> $<br> per jump rope
Angelina_Jolie [31]

Answer:

90 cents

Step-by-step explanation:

you divide 1.80 by 2 and get .9 which is equal to 90 cents

6 0
2 years ago
Read 2 more answers
What is the slope of line segment AB? where A is (-5,3) and B is (3,-3)
Salsk061 [2.6K]

Answer:

D) -3/4

Step-by-step explanation:

Slope is found by using

m= (y2-y1)/(x2-x1) hwere the points are (x1,y1) and (x2,y2)

  = (-3-3)/(3--5)

 = (-6)/(3+5)

 = -6/8

 =-3/4

6 0
4 years ago
What is the area of this trapezoid?
aev [14]

Answer:

The area is 80

Step-by-step explanation:

rectangle in the middle; 24

both triangles on the side; 56

In total; 80

3 0
2 years ago
Lim x→π/2 1-sinx/cot^2x<br>any genious help please ​
Simora [160]

Rewrite the limand as

(1 - sin(<em>x</em>)) / cot²(<em>x</em>) = (1 - sin(<em>x</em>)) / (cos²(<em>x</em>) / sin²(<em>x</em>))

… = ((1 - sin(<em>x</em>)) sin²(<em>x</em>)) / cos²(<em>x</em>)

Recall the Pythagorean identity,

sin²(<em>x</em>) + cos²(<em>x</em>) = 1

Then

(1 - sin(<em>x</em>)) / cot²(<em>x</em>) = ((1 - sin(<em>x</em>)) sin²(<em>x</em>)) / (1 - sin²(<em>x</em>))

Factorize the denominator; it's a difference of squares, so

1 - sin²(<em>x</em>) = (1 - sin(<em>x</em>)) (1 + sin(<em>x</em>))

Cancel the common factor of 1 - sin(<em>x</em>) in the numerator and denominator:

(1 - sin(<em>x</em>)) / cot²(<em>x</em>) = sin²(<em>x</em>) / (1 + sin(<em>x</em>))

Now the limand is continuous at <em>x</em> = <em>π</em>/2, so

\displaystyle\lim_{x\to\frac\pi2}\frac{1-\sin(x)}{\cot^2(x)}=\lim_{x\to\frac\pi2}\frac{\sin^2(x)}{1+\sin(x)}=\frac{\sin^2\left(\frac\pi2\right)}{1+\sin\left(\frac\pi2\right)}=\boxed{\frac12}

4 0
3 years ago
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