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leva [86]
2 years ago
7

Quotient of 120 and 10

Mathematics
2 answers:
saw5 [17]2 years ago
5 0
Quotient is the result of division
120 divided by 10 = 12

therefore your quotient would be 12
MatroZZZ [7]2 years ago
5 0
Quotient=Divide \\ 
 \\ 120 \ divided \ by \ 10 \ is \ 12 \\ 
 \\ Solution:12 \\
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6.
Dmitry [639]

The capacity of the mug is 7/6 cups.

<h3>What is the capacity of the mug?</h3>

Given,

A mug is 3/7 full.

The mug contains 1/2 of a cup of water.

Solution:

Let x be the water.

Water the mug has = 3/7 of x

= 3/7x

Since the water in the mug is 1/2 cup,

3/7x = 1/2

x = 1/2 ÷ 3/7

= 1/2 × 7/3

= 7/6

Therefore,

The capacity of the mug is 7/6 cups.

To learn more about capacity, refer

brainly.com/question/13484626

#SPJ9

4 0
1 year ago
What radius of a circle is required to inscribe an equilateral triangle with an area of 35.074 in2 and an altitude of 7.794 in?
levacccp [35]

Answer:

(C) r=5.2 in

Step-by-step explanation:

firstly, we will draw diagram

we know that

centroid divides altitude into 2:1 form

so, we get

r=\frac{2}{3}\times h

now, we can plug

h=7.794

r=\frac{2}{3}\times 7.794

r=5.196in

so, option-C...............Answer

8 0
2 years ago
Please help with this problem
Natali [406]
I’m pretty sure it’s chad
6 0
3 years ago
Two urns each contain green balls and blue balls. Urn I contains 4 green balls and 6 blue balls, and Urn II contains 6 green bal
Morgarella [4.7K]
Urn 1 = 4 green balls and 6 blue balls, a total of 10 balls
Urn 2 = 6 green balls and 2 blue balls, a total of 8 balls.

Probability of blue balls:
Urn 1 : P = 6/10 
Urn 2 : P = 2/8 

Probability that both balls are blue:
6/10 * 2/8 = 6*2 / 10*8 = 12/80 = 6/40 = 3/20 

Answer is B. 3/20
3 0
3 years ago
Si el máximo común divisor (MCD) de 6432 y 132 disminuye en 8, entonces será igual a: * 1 punto 6 4 -2 -6
swat32

Answer:

4

Step-by-step explanation:

Para empezar el maximo común divisor (MCD) de dos números se refiere al número en común que tienen ambos números, entre los cuales pueden ser divididos. En el caso del máximo se refiere al número más alto posible en que ambos números pueden ser divididos.

Para poder saber esto, es necesario anotar los factores en los cuales pueden ser divididos ambos números. Sin embargo, ya que son cantidades altas, puede tomar mucho tiempo determinar esto, por lo tanto nos vamos a la respuesta final.

Sabemos que el MCD de 132 y 6432 es disminuido en 8 unidades, es decir, se le resta 8 al MCD de esos números, y ese número debe coincidir con alguna de las opciones puesta ahí. Por lo tanto, lo que vamos a hacer para resolverlo rápidamente es sumarle 8 a cada una de las opciones y luego, verificaremos si el número obtenido es divisor de 132 y 6432.

<u>Obtención del MCD original:</u>

a) 6 + 8 = 14

b) 4 + 8 = 12

c) 2 + 8 = 6

d) 6 + 8 = 2

Con estos resultados, veamos cual de ellos es el MCD de 132 y 6432.

<u>Para el 6432:</u>

6432 / 2 = 3216

6432 / 6 = 1072

6432 / 12 = 536

6432 / 14 = 459,24

Podemos observar con estos resultados que el 14 queda descartado al tener un resultado decimal, por lo tanto debe ser 2, 6 o 12. Veamos la cuenta con el 132:

<u>Para el 132:</u>

132 / 2 = 66

132 / 6 = 22

132 / 12 = 11

Podemos observar ahora en este caso que el 132 es divisible entre 12, por lo tanto, es el MCD entre 132 y 6432, asi que se concluye que el resultado de disminuir por 8 el MCD de ambos números es:

<h2>12 - 8 = 4</h2>

Exitos

8 0
2 years ago
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