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Mama L [17]
3 years ago
9

9948 Is it divisible by 2,3,4,5,6,9 or 10 Even or odd

Mathematics
2 answers:
kakasveta [241]3 years ago
7 0
It's even, and divisible by 2, 3, 4, and 6
ratelena [41]3 years ago
6 0
All numbers are divisible. 9948/2 = 4974 9948/3 = 3316 9948/4=2487 9948/5=1989.6 9948/6=1658 9948/9=1105.33333 9948/10=994.8 Hope I helped!
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Given h()<br> - 4x - 4, solve for a when h(x)<br> -8.
Ilia_Sergeevich [38]

Answer:

28

Step-by-step explanation:

this is a function

if h(x) is -8 you would plug it in for x:

-4(-8) -4 a negative × a negative is a positive

32- 4= 28

7 0
3 years ago
Read 2 more answers
A magazine article states that the mean weight of one-year-old boys is the same as that of one-year-old girls. Does the confiden
kirill115 [55]

Answer:

Yes, the confidence interval contradict this statement.

Step-by-step explanation:

The complete question is attached below.

The data provided is:

n_{1}=318\\n_{2}=297\\\bar x_{1}=25\\\bar x_{2}=24.1\\s_{1}=3.6\\s_{2}=3.8

Since the population standard deviations are not provided, we will use the <em>t</em>-confidence interval,

CI=(\bar x_{1}-\bar x_{2})\pm t_{\alpha/2, (n_{1}+n_{2}-2)}\cdot s_{p}\cdot\sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}}

Compute the pooled standard deviation as follows:

s_{p}=\sqrt{\frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}}{n_{1}+n_{2}-2}}=\sqrt{\frac{(318-1)(3.6)^{2}+(297-1)(3.8)^{2}}{318+297-2}}=2.9723

The critical value is:

t_{\alpha/2, (n_{1}+n_{2}-2)}=t_{0.05/2, (318+297-2)}=t_{0.025, 613}=1.962

*Use a <em>t</em>-table.

The 95% confidence interval is:

CI=(\bar x_{1}-\bar x_{2})\pm t_{\alpha/2, (n_{1}+n_{2}-2)}\cdot s_{p}\cdot\sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}}

     =(25-24.1)\pm 1.962\times 2.9723\times \sqrt{\frac{1}{318}+\frac{1}{297}}\\\\=0.90\pm 0.471\\\\=(0.429, 1.371)\\\\\approx (0.43, 1.37)

The 95% confidence interval for the difference between the mean weights is (0.43, 1.37).

To test the magazine's claim the hypothesis can be defined as follows:

<em>H</em>₀: There is no difference between the mean weight of 1-year old boys and girls, i.e. \mu_{1}-\mu_{2}=0.

<em>H</em>ₐ: There is a significant difference between the mean weight of 1-year old boys and girls, i.e. \mu_{1}-\mu_{2}\neq 0.

Decision rule:

If the confidence interval does not consists of the null value, i.e. 0, the null hypothesis will be rejected.

The 95% confidence interval for the difference between the mean weights does not consists the value 0.

Thus, the null hypothesis will be rejected.

Conclusion:

There is a significant difference between the mean weight of 1-year old boys and 1-year old girls.

4 0
4 years ago
Plz help The population of a specific species of a nocturnal mammal is decreasing at a rate of 3.5%/year. The graph models the n
jeka94

Answer:

It is a hard question i can help tho.

Step-by-step explanation:

5 0
4 years ago
5.
Fiesta28 [93]
A.) 135 miles in 3 hours = 45 miles per hr

B.) 22 miles in 1 hour= 22 miles per hr

C.) 7.5 miles in 1/4 hour = 30 miles per hr

D.) 100/3 in 2/3 hour = About 49.9 mph

E.) 97.5 in 1.5 hours = 65 miles per hr
4 0
3 years ago
HELPPPPPPPPPPP
liubo4ka [24]
<span>(A) Find the approximate length of the plank. Round to the nearest tenth of a foot.
Given that the distance of the ground is 3ft.
In order to get the length of the plank,
we can use the this one.

cos 49 = ground / plank
cos 49 = 3 / plank
plank = cos 49 / 3
plank = 0.10 ft

</span><span>(b) Find the height above the ground where the plank touches the wall. Round to the nearest tenth of a foot.
</span><span>
The remaining angle is equal to
angle = 180 - (90+49)
angle = 41

Finding the height.
tan 41 = height / ground
tan 41 = height / 3
height = tan 41 / 3
height = 0.05 ft.

(A) 0.10 feet
(B) 0.05 feet</span>
3 0
4 years ago
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