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3 years ago

Please can you fully factorise these equasions?

2 answers:

5 0

$1)\\ 36x^3-6x=6x(6x^2-1)=6x[( \sqrt{6} \cdot x)^2-1^2]=6x(x \sqrt{6} -1)(x \sqrt{6} +1)\\ \\2)\\12x^3+15x^2=3x^2(4x+3)\\ \\3)\\8x-10x^2=2x(4-5x)$

Murljashka [212]3 years ago

3 0

$36x^3-6x=6x(6x^2-1)=6x[(x\sqrt6)^2-1^2]=6x(x\sqrt6-1)(x\sqrt6+1)\\\\12x^3+15x^2=3x^2(4x+5)\\\\8x-10x^2=2x(4-5x)$

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3 years ago

Read 2 more answers

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