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aev [14]
3 years ago
9

Please can you fully factorise these equasions?

Mathematics
2 answers:
jolli1 [7]3 years ago
5 0
1)\\ 36x^3-6x=6x(6x^2-1)=6x[( \sqrt{6} \cdot x)^2-1^2]=6x(x \sqrt{6} -1)(x \sqrt{6} +1)\\ \\2)\\12x^3+15x^2=3x^2(4x+3)\\ \\3)\\8x-10x^2=2x(4-5x)
Murljashka [212]3 years ago
3 0
36x^3-6x=6x(6x^2-1)=6x[(x\sqrt6)^2-1^2]=6x(x\sqrt6-1)(x\sqrt6+1)\\\\12x^3+15x^2=3x^2(4x+5)\\\\8x-10x^2=2x(4-5x)
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In the second option, he'll buy a membership for $35 and then get the item at a 15% discount. With a 15% discount, the price of the item will be 500 - (500*0.15) = 500 - 75 = $425. And with the membership price, he'll pay a total of 425 + 35 = $460.

The third option is to buy the item online at a 10% discount and pay $4 for the shipping. At 10% discount, the price of the item will be 500 - (500*0.1) = 500 - 50 = $450. And with cost of the shipping, he'll pay a total of 450+4 = $454.


So if he chooses the first option, he'll pay $490. With the second, he'll pay $460. And finally with the third, he'll pay $454.

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