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aev [14]
3 years ago
9

Please can you fully factorise these equasions?

Mathematics
2 answers:
jolli1 [7]3 years ago
5 0
1)\\ 36x^3-6x=6x(6x^2-1)=6x[( \sqrt{6} \cdot x)^2-1^2]=6x(x \sqrt{6} -1)(x \sqrt{6} +1)\\ \\2)\\12x^3+15x^2=3x^2(4x+3)\\ \\3)\\8x-10x^2=2x(4-5x)
Murljashka [212]3 years ago
3 0
36x^3-6x=6x(6x^2-1)=6x[(x\sqrt6)^2-1^2]=6x(x\sqrt6-1)(x\sqrt6+1)\\\\12x^3+15x^2=3x^2(4x+5)\\\\8x-10x^2=2x(4-5x)
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Hello from MrBillDoesMath!

Answer:   f(x) =   (2/3)*x -3   -- which is not a provided answer..


Discussion:


We are given that y + 7 = (2/3) * (x + 6). Multiply out the right hand side:


y + 7 = (2/3) * x + (2/3) * 6 = (2/3) *x + 12/3

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Subtract 7 from both sides:

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or

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Thank you,

MrB


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