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aev [14]
3 years ago
9

Please can you fully factorise these equasions?

Mathematics
2 answers:
jolli1 [7]3 years ago
5 0
1)\\ 36x^3-6x=6x(6x^2-1)=6x[( \sqrt{6} \cdot x)^2-1^2]=6x(x \sqrt{6} -1)(x \sqrt{6} +1)\\ \\2)\\12x^3+15x^2=3x^2(4x+3)\\ \\3)\\8x-10x^2=2x(4-5x)
Murljashka [212]3 years ago
3 0
36x^3-6x=6x(6x^2-1)=6x[(x\sqrt6)^2-1^2]=6x(x\sqrt6-1)(x\sqrt6+1)\\\\12x^3+15x^2=3x^2(4x+5)\\\\8x-10x^2=2x(4-5x)
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Study the function below. f(x) = –3x Label the function as proportional or non-proportional. Explain your reasoning.
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What is the solution to the equation <br> 2x-3/4 ?
amm1812
The solution to this equation is in the picture i’ve put below!

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Kenya jumped 7 1/6 feet. Janet jumped 6 1/3 feet. How much farther did Kenya jump?
jolli1 [7]
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Given limit f(x) = 4 as x approaches 0. What is limit 1/4[f(x)]^4 as x approaches 0?
stepladder [879]

Answer:

\displaystyle 64

General Formulas and Concepts:

<u>Calculus</u>

Limits

Limit Rule [Variable Direct Substitution]:                                                             \displaystyle \lim_{x \to c} x = c

Limit Rule [Variable Direct Substitution Exponential]:                                         \displaystyle \lim_{x \to c} x^n = c^n

Limit Property [Multiplied Constant]:                                                                     \displaystyle \lim_{x \to c} bf(x) = b \lim_{x \to c} f(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle  \lim_{x \to 0} f(x) = 4

<u>Step 2: Solve</u>

  1. Rewrite [Limit Property - Multiplied Constant]:                                           \displaystyle \lim_{x \to 0} \frac{1}{4}[f(x)]^4 = \frac{1}{4} \lim_{x \to 0} [f(x)]^4
  2. Evaluate limit [Limit Rule - Variable Direct Substitution Exponential]:       \displaystyle \lim_{x \to 0} \frac{1}{4}[f(x)]^4 = \frac{1}{4}(4^4)
  3. Simplify:                                                                                                         \displaystyle \lim_{x \to 0} \frac{1}{4}[f(x)]^4 = 64

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

Book: College Calculus 10e

3 0
3 years ago
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SashulF [63]
I think it is 0.64..
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