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Dafna11 [192]
3 years ago
7

A toy manufacturer wants to minimize her cost for producing two lines of toy airplanes. Because of the supply of materials, no m

ore than 40 Flying Bats can be built each day, and no more than 60 Flying Falcons can be built each day. There are enough workers to build at least 70 toy airplanes each day. It costs $12 to manufacture a Flying Bat and $8 to build a Flying Falcon. What is the minimum possible cost each day?
Mathematics
1 answer:
andrey2020 [161]3 years ago
8 0
Since Flying Falcon cost($8) is cheaper than Flying Bat($12), then the minimum possible cost each day would be the maximum possible Flying Falcon produced.
The maximum flying falcon produces is 60/day. Then, the amount of flying bat produced would be:

total= falcon + bat
70= 60+bat
bat= 70-60= 10

The minimum possible cost: falcon * falcon_cost + bat * bat_cost = 60*$8 + 10*$12 = $480+$120= $600
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Suppose that you need to build as many chairs as possible. Each chair requires one seat, one back, and four legs. If you have 12
GrogVix [38]

Answer:

  legs limit the number of chairs that can be built

Step-by-step explanation:

The maximum number of chairs that can be built will be the minimum of the number of parts divided by the number of parts needed for each chair, as computed across the different kinds of parts required.

  seats: 12 available, used 1 per chair: 12/1 = 12 chairs possible

  backs: 15 available, used 1 per chair: 15/1 = 15 chairs possible

  legs: 44 available, used 4 per chair: 44/4 = 11 chairs possible

The maximum number of chairs that can be built will be the minimum of 12, 15, and 11. That is, 11 chairs can be built, limited by the number of available legs.

6 0
2 years ago
Help me on this one for 10 points
nekit [7.7K]

Answer:

m ACG = 17

x = 24

Step-by-step explanation:

1)\ m\ ACG = x - 7 = 90 - 73 = 17

2)\ x - 7 = 17 => x = 17 + 7 = 24

6 0
2 years ago
Read 2 more answers
From the diagram below, if the sides AD = 3 and DC = 27, and BD = X + 3, find x.
Colt1911 [192]

Given:

• AD = 3

,

• DC = 27

,

• BD = x + 3

Let's solve for x.

To solve for x, apply the altitude formula:

\frac{AD}{BD}=\frac{BD}{DC}

Where BD is the altitude.

Cross multiply:

BD^2=AD*DC

Plug in the values and solve for x:

\begin{gathered} (x+3)^2=3*27 \\  \\ (x+3)^2=81 \end{gathered}

Take the square root of both sides:

\begin{gathered} \sqrt{(x+3)^2}=\sqrt{81} \\  \\ x+3=9 \\  \\ \text{ Subtract 3 from both sides:} \\ x+3-3=9-3 \\  \\ x=6 \end{gathered}

Therefore, the value of x is 6 .

ANSWER:

d. 6

4 0
1 year ago
Convert 7/11 to a percent. round the answer to the nearest hundredth
pychu [463]
<h3>Answer:</h3>

63.64%

<h3>Step-by-step explanation:</h3>

7/11 = 7/11 × 100% = (700/11)% ≈ 63.64%

_____

<em>Comment on fractions involving 11</em>

1/11 is the 2-digit repeating decimal 0.09090909...

So, any multiple of 1/11 is a 2-digit repeating decimal with the two digits being the numerator times 9.

Here, we have 7/11, so the 2-digit repeat is 7·9 = 63. That is ...

... 7/11 = 0.63636363...

3 0
3 years ago
A car can travel 105 miles on 7 gallons of gas. How far can it travel on 9 gallons
Wewaii [24]

Find how far the car can travel on one gallon of gas, by dividing total miles by number of gallons:

105 miles / 7 gallons = 15 miles per gallon.


Now multiply that by the number of gallons to find total miles:

15 miles per gallon x 9 gallons = 135 total miles.

6 0
3 years ago
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