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Dafna11 [192]
2 years ago
7

A toy manufacturer wants to minimize her cost for producing two lines of toy airplanes. Because of the supply of materials, no m

ore than 40 Flying Bats can be built each day, and no more than 60 Flying Falcons can be built each day. There are enough workers to build at least 70 toy airplanes each day. It costs $12 to manufacture a Flying Bat and $8 to build a Flying Falcon. What is the minimum possible cost each day?
Mathematics
1 answer:
andrey2020 [161]2 years ago
8 0
Since Flying Falcon cost($8) is cheaper than Flying Bat($12), then the minimum possible cost each day would be the maximum possible Flying Falcon produced.
The maximum flying falcon produces is 60/day. Then, the amount of flying bat produced would be:

total= falcon + bat
70= 60+bat
bat= 70-60= 10

The minimum possible cost: falcon * falcon_cost + bat * bat_cost = 60*$8 + 10*$12 = $480+$120= $600
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algol13

Answer:

its neither

Step-by-step explanation:

supplementary means the angles would equal 180° and complementary means the Angel's would equal 90°

in this case the angles equal to neither.

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3 years ago
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A rectangular piece of metal is 15 in longer than it is wide. Squares with sides 3 in long are cut from the four corners and the
ziro4ka [17]

Answer:

The original dimensions of the piece of metal are

Length: 36 inches

Width: 21 inches

Step-by-step explanation:

Let

x ----> the original length pf the piece of metal

y ----> the original width pf the piece of metal

we know that

x=y+15 ----> equation A

The volume of the box is equal to

V=LWH

we have

V=1,350\ in^3

L=(x-3-3)=(x-6)\ in\\W=(y-3-3)=(y-6)\ in

H=3\ in

substitute in the formula of volume

1,350=(x-6)(y-6)(3) ----> equation B

substitute equation A in equation B

1,350=(y+15-6)(y-6)(3)

solve for y

450=(y+9)(y-6)

y^2-6y+9y-54=450\\y^2+3y-504=0

Solve the quadratic equation by graphing

using a graphing tool

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5 0
2 years ago
Evaluate this expression. 5^-3
sweet-ann [11.9K]

Answer:

\Huge \boxed{\frac{1}{125}}

Step-by-step explanation:

<h2>Order of operations</h2>

PEMDAS

Parenthesis, exponent, multiply, divide, add, and subtract from left to right.

Do exponent.

\displaystyle \frac{1}{5^3}

\displaystyle 5^3=5\times5\times5=125

\displaystyle \frac{1}{125}=125

\large \boxed{\frac{1}{125}}, which is our answer.

Hope this helps!

4 0
3 years ago
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21/35

use the 7 times table

divide the fraction by 7

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3/5

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devlian [24]

Answer:

b ≤ -4

Step-by-step explanation:

4b−4≤−20

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Divide both sides by 4

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