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Natasha_Volkova [10]
1 year ago
5

From the diagram below, if the sides AD = 3 and DC = 27, and BD = X + 3, find x.

Mathematics
1 answer:
Colt1911 [192]1 year ago
4 0

Given:

• AD = 3

,

• DC = 27

,

• BD = x + 3

Let's solve for x.

To solve for x, apply the altitude formula:

\frac{AD}{BD}=\frac{BD}{DC}

Where BD is the altitude.

Cross multiply:

BD^2=AD*DC

Plug in the values and solve for x:

\begin{gathered} (x+3)^2=3*27 \\  \\ (x+3)^2=81 \end{gathered}

Take the square root of both sides:

\begin{gathered} \sqrt{(x+3)^2}=\sqrt{81} \\  \\ x+3=9 \\  \\ \text{ Subtract 3 from both sides:} \\ x+3-3=9-3 \\  \\ x=6 \end{gathered}

Therefore, the value of x is 6 .

ANSWER:

d. 6

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Under average driving conditions, the life lengths of automobile tires of a certain brand are found to follow an exponential dis
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a) P(X>30000)=1-( 1- e^{-\frac{30000}{30000}})=e^{-1}=0.368

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Step-by-step explanation:

Previous concepts

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P(X=x)=\lambda e^{-\lambda x}, x>0

And 0 for other case. Let X the random variable that represent "life lengths of automobile tires of a certain brand" and we know that the distribution is given by:

X \sim Exp(\lambda=\frac{1}{30000})

The cumulative distribution function is given by:

F(X) = 1- e^{-\frac{x}{\mu}}

Part a

We want to find this probability:

P(X>30000) and for this case we can use the cumulative distribution function to find it like this:

P(X>30000)=1-( 1- e^{-\frac{30000}{30000}})=e^{-1}=0.368

Part b

For this case w want to find this probability

P(X>30000|X>15000)

We have an important property on the exponential distribution called "Memoryless" property and says this:

P(X>a+t| X>t)=P(X>a)  

On this case if we use this property we have this:P(X>30000|X>15000)=P(X>15000+15000|X>15000)=P(X>15000)

We can use the definition of the density function and find this probability:

P(X>15000)=1-( 1- e^{-\frac{15000}{30000}})=e^{-0.5}=0.607

7 0
2 years ago
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