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Fynjy0 [20]
3 years ago
9

Statistics..

Mathematics
1 answer:
ch4aika [34]3 years ago
7 0
1 of 2 type of lettuces
1 of 4 vegetables
1 of 7 dressings

2*4*7 = 56 different salads
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I need to figure this out for a quiz in APEX. I can get the rest if I understand how to do this one.
KIM [24]
The answer is b
(-1,3,5)

Hope this helps!
8 0
3 years ago
Lily took a survey of 80 students on 7th grade and 150 students in 8th grade she found that 80% of the 7th graders like country
Anarel [89]

Answer:

Step-by-step explanation:

80 over 100*150

80 divided by 100=0.8 *150=1208student

0.8 *60=48

8 0
3 years ago
In a population of 10,000, there are 5000 nonsmokers, 2500 smokers of one pack or less per day, and 2500 smokers of more than on
Kazeer [188]

Answer:

In one month, we will have 4,950 non-smokers, 2,650 smokers of one pack and 2,400 smokers of more than one pack.

In two months, we will have 4,912 non-smokers, 2,756 smokers of one pack and 2,332 smokers of more than one pack.

In a year, we will have 4,793 non-smokers, 3,005 smokers of one pack and 2,202 smokers of more than one pack.

Step-by-step explanation:

We have to write the transition matrix M for the population.

We have three states (nonsmokers, smokers of one pack and smokers of more than one pack), so we will have a 3x3 transition matrix.

We can write the transition matrix, in which the rows are the actual state and the columns are the future state.

- There is an 8% probability that a nonsmoker will begin smoking a pack or less per day, and a 2% probability that a nonsmoker will begin smoking more than a pack per day. <em>Then, the probability of staying in the same state is 90%.</em>

-  For smokers who smoke a pack or less per day, there is a 10% probability of quitting and a 10% probability of increasing to more than a pack per day. <em>Then, the probability of staying in the same state is 80%.</em>

- For smokers who smoke more than a pack per day, there is an 8% probability of quitting and a 10% probability of dropping to a pack or less per day. <em>Then, the probability of staying in the same state is 82%.</em>

<em />

The transition matrix becomes:

\begin{vmatrix} &NS&P1&PM\\NS&  0.90&0.08&0.02 \\  P1&0.10&0.80 &0.10 \\  PM& 0.08 &0.10&0.82 \end{vmatrix}

The actual state matrix is

\left[\begin{array}{ccc}5,000&2,500&2,500\end{array}\right]

We can calculate the next month state by multupling the actual state matrix and the transition matrix:

\left[\begin{array}{ccc}5000&2500&2500\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] =\left[\begin{array}{ccc}4950&2650&2400\end{array}\right]

In one month, we will have 4,950 non-smokers, 2,650 smokers of one pack and 2,400 smokers of more than one pack.

To calculate the the state for the second month, we us the state of the first of the month and multiply it one time by the transition matrix:

\left[\begin{array}{ccc}4950&2650&2400\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] =\left[\begin{array}{ccc}4912&2756&2332\end{array}\right]

In two months, we will have 4,912 non-smokers, 2,756 smokers of one pack and 2,332 smokers of more than one pack.

If we repeat this multiplication 12 times from the actual state (or 10 times from the two-months state), we will get the state a year from now:

\left( \left[\begin{array}{ccc}5000&2500&2500\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] \right)^{12} =\left[\begin{array}{ccc}4792.63&3005.44&2201.93\end{array}\right]

In a year, we will have 4,793 non-smokers, 3,005 smokers of one pack and 2,202 smokers of more than one pack.

3 0
3 years ago
Z + 6 over 3 = 2z over 4
Black_prince [1.1K]
    \frac{z + 6}{3} = \frac{2z}{4}   Multiply both sides by 3
    z + 6 = \frac{(3)2z}{4}   Multiply both sides by 4
(4)z + 6 = (3)2z   Simplify
4z + 24 = 6z   Subtract 4z from both sides
        24 = 2z   Divide both sides by 2
         12 = z     Flip the sides to make it easier to read
          z = 12
7 0
3 years ago
What’s the answer to this (-4y+5)-(2y+4)=
goldfiish [28.3K]

Answer:

You can only simplify it down to -6y+1

Step-by-step explanation:

Since there is nothing past the equals sign, there is no way to solve it, only a way to simplify it. Hope this helps!

5 0
3 years ago
Read 2 more answers
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