Answer:
Step-by-step explanation:
Given: Dimensions of a big locker are 0.5 m × 0.6 m × 1.2 m
Dimensions of a small locker are 0.5 m × 0.6 m × 
(as height of small locker is half the height of big locker )
To find: total volume of one big locker and one small locker
Solution:
Volume of cuboid = length × breadth × height
Total volume of one big locker and one small locker = Total volume of one big locker + total volume of one small locker
= 
Answer:
Hypotenuse= 10, short leg= 5
Step-by-step explanation:
Answer:
Step-by-step explanation:
-The locust population grows by a factor and can therefore be modeled by an exponential function of the form:
Where:
is the population after t days.
is the initial population given as 7600
is the rate of growth
is time in days
-Given that the growth is by a factor of 5( equivalent to 500%), the r value will be 5
-The population increases by a factor of 5 every 22 days. therefore at any time instance, t will be divided by 22 to get the effective time for calculations.
Hence, the exponential growth function will be expressed as:
2,300,000 + 510,000 = 2,810,000 them move a decimal to where is greater then 1
2.81 x 10^6 but wait, there isnt an answer for this so it has to be 28.1 x 10^5 witch is B
Answer: y = 6 mi. .
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Explanation:
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Area of a triangle = (½) * (base) * (height) ;
or, A = (½) * b * h ; or, A = b*h / 2 ;
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Given: A = 24.3 mi ² ;
b = 8.1 mi
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Find the height, "h" ; (in units of "miles", or , "mi" ).
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Plug in the known values into the formula:
24.3 mi ² = (½) * (8.1 mi) *(h) ;
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Solve for "h" (height) ;
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(½) * (8.1 mi) = 4.05 mi ;
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Rewrite:
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24.3 mi² = (4.05 mi) *(h) ; Solve for "h" ;
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Divide each side of the equation by "(4.05 mi)" ; to isolate "h" on one side of the equation ; and to solve for "h" ;
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24.3 mi² / 4.05 mi = (4.05 mi) *(h) / 4.05 mi ;
→ 6 mi = h ; ↔ h = 6 mi.
→ h = y = 6 mi.
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