All categories

3 years ago

Not all will be used, which are correct?

Mathematics

1 answer:

marishachu [46]3 years ago

3 0

Answer:

Figure 1

Step-by-step explanation:

A will be at (-5, 3)

B will be at (-4, 1)

C will be at (-3, 2)

D will be at (-2, 1)

E will be at (-2, 5)

F will be at (-3, 4)

G will be at (-4, 5)

You might be interested in

0.2% of what number is 12?

Ratling [72]

Percent mean parts out of 100 0.2%=0.2/100=0.02/10=0.002/1=0.002 'of' means multiply 'what number'=x 'is' means '=' so 0.2% of what number is 12 0.002 times x=12 divide both sides by 0.002 x=6000 the number is 6000

3 0

4 years ago

Read 2 more answers

Find the value of x 7x+2=16<br>pls explain

miskamm [114]

Answer:

Step-by-step explanation:

Given

7x + 2 = 16

Subtracting 2 from both sides

7x + 2 - 2 = 16 - 2

7x = 14

Dividing both sides by 7

7x / 7 = 14 /7

x = 2

Hope it will help :)

6 0

3 years ago

Read 2 more answers

What’s 32 divided by 1.19

Kaylis [27]

Answer:

26.8907563 or if your rounding it then 26.7

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati

makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

$y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\$

And the second one would be

$y = 2-x \,\,\,\,\,, 1 \leq x \leq 2$ .

If you rotate the first region around the "y" axis you get that

$A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51$

And if you rotate the second region around the "y" axis you get that

$A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188$

And the sum would be 2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first region around the x axis you get that

$A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708$

And if you rotate the second region around the x axis you get that

$A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472$

And the sum would be 1.5708+1.0472 = 2.618

7 0

4 years ago

Help wit this? 10m-8m+2+10

GenaCL600 [577]

Answer:

2m+12

Step-by-step explanation:

add like terms

2m+12

7 0

3 years ago