<span>ABC =22° because AB and BC are congruent
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Answer:
2/5
Step-by-step explanation:
m=change in y/change in x
m=
m = 6-(4)/3-(-2)
m=2/3-(-2)
m= 2/3+2
m=2/5
X = -3.
The distance from p(-9, 0, 0) is
d = sqrt((x+9)^2 + y^2 + z^2)
The distance from q(3,0,0) is
d = sqrt((x-3)^2 + y^2 + z^2)
Let's set them equal to each other.
sqrt((x+9)^2 + y^2 + z^2) = sqrt((x-3)^2 + y^2 + z^2)
Square both sides, then simplify
(x+9)^2 + y^2 + z^2 = (x-3)^2 + y^2 + z^2
x^2 + 18x + 81 + y^2 + z^2 = x^2 - 6x + 9 + y^2 + z^2
18x + 81 = - 6x + 9
24x + 81 = 9
24x = -72
x = -3
So the desired equation is x = -3 which defines a plane.
Answer:
the answer is the option C
m∠2 = 99° and m∠4 = 99°
Step-by-step explanation:
edg 2020
53 degrees because it's complementary.