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3 years ago

The rules and guidelines for appropriate computer mediated communication are called ________.

2 answers:

5 0

The correct answer is netiquette. This term refers to the acceptable and proper way to communicate on the Internet. The term is a combination of the words "Internet" and "etiquette." Etiquette is defined as the standard code of conduct for polite behavior in a particular context. In this case, the context is the Internet and the two words have been combined to create a new word, netiquette.

lora16 [44]3 years ago

3 0

Answer:

its c

Explanation:

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fill in the balenkes ) 1)there are ................................... function keys on the keybord 2)pressing the end key moves

Doss [256]

Answer:

1.) There are 12 function keys 2.) The return Key

Explanation:

6 0

3 years ago

The return value is a one-dimensional array that contains two elements. These two elements indicate the rows and column indices

erma4kov [3.2K]

Answer:

In Java:

import java.util.Scanner;

import java.util.Arrays;

public class Main {

public static void main(String args[]) {

Scanner input = new Scanner(System.in);

int row, col;

System.out.print("Rows: "); row = input.nextInt();

System.out.print("Cols: "); col = input.nextInt();

int[][] Array2D = new int[row][col];

System.out.print("Enter array elements: ");

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

Array2D[i][j] = input.nextInt();

} }

int[] maxarray = findmax(Array2D,row,col);

System.out.println("Row: "+(maxarray[0]+1));

System.out.println("Column: "+(maxarray[1]+1));

}

public static int[] findmax(int[][] Array2D,int row, int col) {

int max = Array2D[0][0];

int []maxitem = new int [2];

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

if(Array2D[i][j] > max){

maxitem[0] = i;

maxitem[1] = j; } } }

return maxitem;

}

Explanation:

The next two lines import the scanner and array libraries

import java.util.Scanner;

import java.util.Arrays;

The class of the program

public class Main {

The main method begins here

public static void main(String args[]) {

The scanner function is called in the program

Scanner input = new Scanner(System.in);

This declares the array row and column

int row, col;

This next instructions prompt the user for rows and get the row input

System.out.print("Rows: "); row = input.nextInt();

This next instructions prompt the user for columns and get the column input

System.out.print("Cols: "); col = input.nextInt();

This declares the 2D array

int[][] Array2D = new int[row][col];

This prompts the user for array elements

System.out.print("Enter array elements: ");

The following iteration populates the 2D array

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

Array2D[i][j] = input.nextInt();

} }

This calls the findmax function. The returned array of the function is saved in maxarray

int[] maxarray = findmax(Array2D,row,col);

This prints the row position

System.out.println("Row: "+(maxarray[0]+1));

This prints the column position

System.out.println("Column: "+(maxarray[1]+1));

The main method ends here

}

The findmax function begins here

public static int[] findmax(int[][] Array2D,int row, int col) {

This initializes the maximum to the first element of the array

int max = Array2D[0][0];

This declares maxitem. The array gets the position of the maximum element

int []maxitem = new int [2];

The following iteration gets the position of the maximum element

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

if(Array2D[i][j] > max){

maxitem[0] = i; -- The row position is saved in index 0

maxitem[1] = j; -- The column position is saved in index 1} } }

This returns the 1 d array

return maxitem;

}

7 0

3 years ago

How many bits are required to store the text of the number 150 in ascii?

kaheart [24]

The correct answer of the given question above would be 24 BITS. The number of bits that are required to store the text of the number 150 in ASCII would be 24 bits. ASCII means American Standard Code for Information Interchange. Hope this answer helps.

7 0

3 years ago

Read 2 more answers

Semiconductor memory is used mainly for primary storage even with its high cost. In another hand, the magnetic tape is the cheap

Charra [1.4K]

Storage costs of magnetic tape are much lower than semiconductor storage (chip storage), but they take longer to access because they are not on-board the system and have to be added manually. Chip memory, on the other hand, can be used as primary storage for a system even with a higher cost because it's typically directly connected to the system board and is much more easily accessible by the system.

8 0

4 years ago

2.3 Code Practice: Question 2

IRISSAK [1]

Answer:

Codes are given below:

Explanation:

Since the language is not specified, I am writing it in c++. I have added comments to explain each line

#include <iostream>

using namespace std;

int main() //Start of main function

{

int feet1, feet2 , inches1, inches2, t_feet, t_inches; //declaring the variables

cout << "Enter the Feet for the first piece of fabric:"<<endl;

cin >> feet1; //this will take the feet piece1 as an input

cout << "Enter the Inches for the first piece of fabric:"<<endl;

cin >> inches1; //this will take the inches piece1 as an input

cout << "Enter the Feet for the second piece of fabric:"<<endl;

cin >> feet2; //this will take the feet piece2 as an input

cout << "Enter the Inches for the second piece of fabric:"<<endl;

cin >> inches2; //this will take the inches piece2 as an input

t_feet = feet1 + feet2; //adding the feet

t_inches = inches1 + inches2; //adding the inches

if (t_inches> 11) //checkimg if the inches are greater than 11

{

t_feet = t_feet + t_inches/12; //converting inches to feet that are greater than 12

t_inches = t_inches%12; //getting the remaining inches after converting them to feet

}

cout <<"The total length: " << t_feet <<" feet and" << t_inches <<" inches" << endl;

return 0;

} //End of main function

3 0

3 years ago