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The logical expressions are
- (X NOR Y ) OR Z ⇒
- (A NAND B) AND NOT C ⇒
<u>Logical expression 1</u>
X and Y are linked by the NOR gate.
So, we have:
X NOR Y
The X NOR Y is linked to Z by the OR gate.
So, we have:
(X NOR Y) OR Z
Hence, the logical expression is (X NOR Y ) OR Z ⇒
<u>Logical expression 2</u>
A and B are linked by the NAND gate.
So, we have:
A NAND B
The A NAND B is linked to C by the AND gate.
So, we have:
(A NAND B) AND C
Hence, the logical expression is (A NAND B) AND NOT C ⇒
See attachment for the truth tables
Read more about truth tables at:
#SPJ1
Answer:
Explanation:
Considering the number are stored using binary notations.
If there are total 86 bits and 1 bit is used as sign bit. Then in total one can have bit combinations since a bit can be either stored as 0 or as 1.
Therefore, the largest number that can be stored will be .
To understand it in better way let's scale down the problem to 3 bits representation. The largest number that can be stored using 3 bits is 111 which in decimal form is 7 and is equal to .