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densk [106]
3 years ago
14

Both aliases and functions can be used to store commands that can be executed, but functions can also accept positional paramete

rs.
a. True
b. False
Computers and Technology
1 answer:
Aliun [14]3 years ago
6 0

Answer:

The answer is "True".

Explanation:

  • Alias command is normally used for shortening or chain terminal commands with each other. These commands include many shells that are ash, bash, csh, and ksh. The purpose is to use these commands is read and execute commands.  
  • A function is a group of statements that are used to perform a specifics task. In other words, we can say that a function will take values that are passed by the user and somehow manipulate those values for executing commands and function parameters are known as positional parameters.

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Sholpan [36]

Meee plzzzzz First!............

4 0
3 years ago
Read 2 more answers
How can you ensure that your web pages are compliant with a w3c standard?
miss Akunina [59]
Use a code validation tool.
6 0
4 years ago
In mathematics, "quadrant I" of the cartesian plane is the part of the plane where x and y are both positive. Given a variable,
lbvjy [14]

Answer:

#include <iostream>

using namespace std;

struct Cartesian {

double x;

double y;

};

int main() {

// creating a pointer p of type struct Cartesian

struct Cartesian *p = new Cartesian ;

cout << " Enter x: ";

// accessing the structure variable x by arrow "->"

cin >> p->x;

cout << "Enter y: ";

// accessing the structure variable y by arrow "->"

cin >> p->y;

// expression to check whether x and y lie in Quadrant 1

if (p->x > 0 && p->y > 0) {

 cout << "X and Y are in Quadrant 1 ";

}

else

{

 cout << "x And y are not in Quadrant 1";

}

// deleting the struct pointer p

delete p;

return 0;

}

Explanation:

in order to locate memory in heap, keyword "new" is used in C++ so,

struct Cartesian *p = new Cartesian ;

in order to access data members of the structure using pointer we always use an arrow "->". otherwise a dot oprerator is used to access data members.

in order to check whether x and y lie in 1st quadrent, we must use && operator in our if condition. so

if (p->x > 0 && p->y > 0)

&& will return true iff x and y both are +ve.

deleting the struct pointer p is important beacuse we are allocating memory in heap so heap memory should be used a resource and must be release when not needed otherwise it can cause memory leakage problems. so  

delete p;

5 0
3 years ago
Answer the following questions:
victus00 [196]

Answer:

The answer to the following questions can be given as:

Question: 1

value of foo is = 1020

Question: 2

Output of the code is = false

Question: 3

function add(a, b)

{

 return a && b ? a + b : function (c) { return a + c; };

}

var a=add(2,5);

var x=add(2)(5);

print(a);

print(x);

output:  

7

7

Question: 4

"goh angasal a m'i"

Question: 5

In this we check that if in the window a foo function exists. otherwise we set windows.foo to bar.

Question: 6

first alert shows the value "Hello World";

second alert shows value ReferenceError, In this bar not defined.

Question: 7

The value of foo.length is  2

Question: 8

The value of foo.x is undefined

Question: 9

Function print = "one", "three", "two" .

Question :10

It is difficult to define because doSomethingElse() function is not defined.

Explanation:

In question 1 the value of the foo variable is 1020 because we perform the string concat operation.

In question 2 Output of the code is false because float value keeps in binary and when we convert 0.1 or 0.2 to binary so it is not the same.

In question 3 the output of both functions is 7.

In question 4 the output is goh angasal a m'i because In this code we use the reverse() function, split() function and join() function. Reverse function reverses the value. split function splits the value and join function join all the value of the string in a line.

In question 5 we check the value.

In question 6, the first output is Hello World and second is ReferenceError.

In question 7, the value of foo.length is 2 because this foo array we insert only 2 values.

In question 8, the value of foo.x is undefined because in the variable we reset the value of foo all together, so foo.x value is undefined.

In the question 9 function print "one",  

"three",  

"two" because In the function first, we print the message that is "one" then we define a function in this function we print the value  

"two" but before creating object we call the "three" so the print value is "one",  

"three",  

"two".

In question 10 function, the output of this function is undefined.

3 0
3 years ago
What will be displayed after code corresponding to the following pseudocode is run? Main Set OldPrice = 100 Set SalePrice = 70 C
Tatiana [17]

Answer:

A jacket that originally costs $ 100 is on sale today for $ 80                                    

Explanation:

Main : From here the execution of the program begins

Set OldPrice = 100  -> This line assigns 100 to the OldPrice variable

Set SalePrice = 70   -> This line assigns 70to the SalePrice variable

Call BigSale(OldPrice, SalePrice)  -> This line calls BigSale method by passing OldPrice and SalePrice to that method

Write "A jacket that originally costs $ ", OldPrice  -> This line prints/displays the line: "A jacket that originally costs $ " with the resultant value in OldPrice variable that is 100

Write "is on sale today for $ ", SalePrice  -> This line prints/displays the line: "is on sale today for $ " with the resultant value in SalePrice variable that is 80

End Program -> the main program ends

Subprogram BigSale(Cost, Sale As Ref)  -> this is a definition of BigSale method which has two parameters i.e. Cost and Sale. Note that the Sale is declared as reference type

Set Sale = Cost * .80  -> This line multiplies the value of Cost with 0.80 and assigns the result to Sale variable

Set Cost = Cost + 20  -> This line adds 20 to the value of Cost  and assigns the result to Cost variable

End Subprogram  -> the method ends

This is the example of call by reference. So when the method BigSale is called in Main by reference by passing argument SalePrice to it, then this call copies the reference of SalePrice argument into formal parameter Sale. Inside BigSale method the reference &Sale is used to access actual argument i.e. SalePrice which is used in BigSale(OldPrice, SalePrice) call. So any changes made to value of Sale will affect the value of SalePrice

So when the method BigSale is called two arguments are passed to it OldPrice argument and SalePrice is passed by reference.

The value of OldPrice is 100 and SalePrice is 70

Now when method BigSale is called, the reference &Sale is used to access actual argument SalePrice = 70

In the body of this method there are two statements:

Sale = Cost * .80;

Cost = Cost + 20;

So when these statement execute:

Sale = 100 * 0.80 = 80

Cost = 100 + 20 = 120

Any changes made to value of Sale will affect the value of SalePrice as it is passed by reference. So when the Write "A jacket that originally costs $ " + OldPrice Write "is on sale today for $ " + SalePrice statement executes, the value of OldPrice remains 100 same as it does not affect this passed argument, but SalePrice was passed by reference so the changes made to &Sale by statement in method BigSale i.e.  Sale = Cost * .80; has changed the value of SalePrice from 70 to 80 because Sale = 100 * 0.80 = 80. So the output produced is:

A jacket that originally costs $ 100 is on sale today for $ 80                              

7 0
3 years ago
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