The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 
/2!+...........
Given a function f(x)=9/x,a=-4.
We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.
The taylor series of a function f(x)=
Where the terms in f prime 
(a) represent the derivatives of x valued at a.
For the given function.f(x)=8/x and a=-4.
So,f(a)=f(-4)=8/(-4)=-2.
(a)=(-4)=-8/(
=-8/16
=-1/2
The series of f(x) is as under:
f(x)=f(-4)+
=-2+2(x+4)/1!-24/16 /2!+...........
Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 /2!+...........
Learn more about taylor series at brainly.com/question/23334489
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The answer is selections 1 and 4
Firstly, since these two fractions have the same denominator, add the numerators up: 
While it appears that the answer is -6/4, you can further simplify it by dividing the numerator and denominator by 2: 
<u>Your answer is 
</u>
Answer:
D
Step-by-step explanation:
5 ÷ 8 = 0.625 = 62.5%
Answer:
By the angles and sides, but if you need more help here is a link to a video that could be pretty helpful.
Step-by-step explanation:
https://www.khanacademy.org/math/cc-fourth-grade-math/plane-figures/imp-classifying-triangles/v/scalene-isosceles-equilateral-acute-right-obtuse#:~:text=Learn%20to%20categorize%20triangles%20as,acute%2C%20right%2C%20or%20obtuse.
