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Citrus2011 [14]
3 years ago
9

The ratio of roosters to chickens is 2 to 8. If there are 5 roosters, how many chickens are there?

Mathematics
2 answers:
a_sh-v [17]3 years ago
7 0

Answer:

Roosters to chickens is 2 to 8

That means where there are 2 roosters, there are 8 chickens.

Simplify the ratio 2:8

The ratio can be simplified to 1:4

So, for 1 rooster, there are 4 chickens.

Now, the question says that if there are 5 roosters, how many chickens will there be?

1 rooster to 4 chickens

5 roosters to ? chickens

We went from 1 rooster to 5 rooster. We multiplied by 5.

To find out how many chickens there are for 5 roosters, multiply 4 chickens by 5.

4 * 5 = 20

Where there are 5 roosters, there will be 20 chickens.

Another way to solve is as follows:

Your final answer is 20 chickens.

Step-by-step explanation:

Aloiza [94]3 years ago
3 0
Roosters to chickens is 2 to 8

That means where there are 2 roosters, there are 8 chickens.

Simplify the ratio 2:8
The ratio can be simplified to 1:4

So, for 1 rooster, there are 4 chickens.

Now, the question says that if there are 5 roosters, how many chickens will there be?

1 rooster to 4 chickens
5 roosters to ? chickens

We went from 1 rooster to 5 rooster. We multiplied by 5.
To find out how many chickens there are for 5 roosters, multiply 4 chickens by 5.

4 * 5 = 20

Where there are 5 roosters, there will be 20 chickens.

Another way to solve is as follows:

\frac{2}{8} =\frac{5}{x}\\\\\sf{Cross~multiply}\\\\2x = 5\times 8\\\\2x = 40\\\\x = 20\\\\\boxed{\bf{x=20}}

Your final answer is 20 chickens.<span />
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Nikitich [7]
115% of the price is 270,25
115*x/100=270,25
x=270,25*100/115
x=235  $ is the price

270,25-235= 35,25 $ is the tax
8 0
3 years ago
The new ointment was applied to four locations, and a control was applied to the other four. How many different choices were the
lubasha [3.4K]

Answer:

there are 70 possible choices for the four locations to apply the new ointment

Step-by-step explanation:

Since we have a total of 8 locations ( 4 to the new ointment and 4 to the control) ,  each one can be chosen and since the order of the locations that are chosen for the new ointment is not relevant  , then we know that the number of choices is given by the number of combinations of 4 elements in 8

number of combinations = 8 possible locations to the first ointment * 7 possible locations to the second ( since the first one was already located) * 6 to the third * 5 locations for the fourth / number of times the same combination is repeated ( the same locations but in different positions) = 8*7*6*5 / (4 possible positions for the first ointment* 3 possible positions to the second ointment (since the first one was already located * 2 possible positions of the third * 1 possible position of the fourth)

therefore

number of combinations = 8*7*6*5/(4*3*2*1 ) = 8!/((8-4)!*4!) = 70 possible combinations

thus there are 70 possible choices for the four locations to apply the new ointment

6 0
3 years ago
2/3 - 4x + 7/2 = -9x + 5/6 apply the properties.. step by step
Nutka1998 [239]

Answer:

x=5/13

Step-by-step explanation:

2/3+7/2=9x+5/6+4x

2/3+7/2-5/6=9x+4x

lcm of 2,3,6=6

2/3=4/6      7/2=21/6       5/6=5/6

4/6+21/6-5/6=9x+4x

30/6=13x

5=13x

x=5/13

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marusya05 [52]

This looks confusing. Can you try reposting this to make it look clear?

4 0
3 years ago
Read 2 more answers
Please Help! In which of the following intervals does the trigonometric inequality sec(x)
timofeeve [1]

Step-by-step explanation:

sec(x) = 1/cos(x)

cot(x) = cos(x)/sin(x)

sec is smaller than cot, if cos is negative (making sec negative) and sin is negative (making cot positive).

and that is true for the third quadrant.

which is pi < x < 3×pi/2

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