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asambeis [7]
3 years ago
11

Situation:

Mathematics
1 answer:
Arturiano [62]3 years ago
8 0

Answer:

t = 6162  years

Step-by-step explanation:

Apparently you are asked to use the constant k = 0.0001 instead of the most common 0.00012. We'll answer the problem using such number you typed, but make sure that there is no omission in your typing.

The equation to use is that for carbon decay:

N(t)=N_0\,e^{-0.0001\,\,t}

If the skull contains 54% of its original amount of C14, then that means that :

N(t)=0.54 \,\,N_0

we use this to solve for the time (t) in our equation:

0.54\,\,N_0=N_0\,e^{-0.0001\,\,t}\\\frac{0.54\,\,N_0}{N_0}=e^{-0.0001\,\,t}\\0.54=e^{-0.0001\,\,t}\\ln(0.54)=-0.0001\,\,t\\t=\frac{ln(0.54)}{-0.0001} \\t=6161.86\,\,years

which rounded to the nearest year as requested gives :

t = 6162  years

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Write two inequalities that would have the solution set as graphed below.
Komok [63]

Answer:

The answer is x > -1

Step-by-step explanation:

This is because if it were a closed circle, it would have to the include the inequality -1 but since it is an opened circle, that inequality is not included. So in conclusion, Any number could be used to represent x as long as it is a greater number than -1. I hope this makes sense.

7 0
3 years ago
Which expression is equivalent to 24b-34ab ? A- 4b(6-8a) B- 4b(6b-8ab) C- 2b(12-17a) D- 2b(12-17ab)
Montano1993 [528]

Answer:

c.

Step-by-step explanation:

hope this helped

5 0
3 years ago
Given the pre-image ABCD and the image after a dilation, A'B'C'D', what is true about the polygons? Check all that apply. The le
vazorg [7]
<h2>Answer </h2>

You should check the following:

The length of AB is 2

The length of A'B' is 3

The scale factor is \frac{3}{2}

<h2>Explanation</h2>

- To find the length of AB, we will use the distance formula:

d(A,B)=|x_{1}-x_{2}|

From the picture we can infer that x_{1}=2 and x_{2}=4, so let's replace the values.

d(A,B)=|2-4|

d(A,B)=|-2|

d(A,B)=2

The length of AB is 2, so you should check the first answer

- To find the length of A'B', we will use the distance formula one more time:

From the picture we can infer that x_{1}=3 and x_{2}=6, so let's replace the values.

d(A',B')=|3-6|

d(A',B')=|-3|

d(A',B')=3

Since the length of A'B' is 3, you should also check the second answer as well.

- In a transformation (in this case a dilation) the pre-image is the original shape and the image is the shape after the transformation.

Since the image is bigger than the pre-image, the third answer is false.

- Let k be the scale factor

We know that the length of AB is 2 and we need to multiply that length by the scale factor to get length of A'B' i.e 3, so:

2k=3

k=\frac{3}{2}

Since the scale factor is \frac{3}{2}, you should check the fourth answer as well.

- We already prove that the scale factor is \frac{3}{2}, so the fifth answer is false.

5 0
4 years ago
Read 2 more answers
I need help please !!!!
agasfer [191]
8^{b-1}=2^{4b+4}\\\\\left(2^3\right)^{b-1}=2^{4b+4}\\\\2^{3(b-1)}=2^{4b+4}\iff3(b-1)=4b+4\\\\3b-3=4b+4\ \ \ |+3\\\\3b=4b+7\ \ \ |-4b\\\\-b=7\to \boxed{b=-7}

\text{check:}\\\\L_s=8^{-7-1}=8^{-8}=(2^3)^{-8}=2^{3\cdot(-8)}=2^{-24}\\\\R_s=2^{4\cdot(-7)+4}=2^{-28+4}=2^{-24}\\\\L_s=R_s\ \ \ \text{CORRECT :)}

\text{Used:}\\(a^n)^m=a^{n\cdot m}

4 0
3 years ago
I need help on this question
Pani-rosa [81]

B. 3

the preimage points were both multiplied by 3, if it were to go from (12, -6) to (4, -2), that would be 1/3

6 0
3 years ago
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