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asambeis [7]
3 years ago
11

Situation:

Mathematics
1 answer:
Arturiano [62]3 years ago
8 0

Answer:

t = 6162  years

Step-by-step explanation:

Apparently you are asked to use the constant k = 0.0001 instead of the most common 0.00012. We'll answer the problem using such number you typed, but make sure that there is no omission in your typing.

The equation to use is that for carbon decay:

N(t)=N_0\,e^{-0.0001\,\,t}

If the skull contains 54% of its original amount of C14, then that means that :

N(t)=0.54 \,\,N_0

we use this to solve for the time (t) in our equation:

0.54\,\,N_0=N_0\,e^{-0.0001\,\,t}\\\frac{0.54\,\,N_0}{N_0}=e^{-0.0001\,\,t}\\0.54=e^{-0.0001\,\,t}\\ln(0.54)=-0.0001\,\,t\\t=\frac{ln(0.54)}{-0.0001} \\t=6161.86\,\,years

which rounded to the nearest year as requested gives :

t = 6162  years

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Benny wants to make cookies.To make cookies, he needs 7/3 cups of flour per batch of cookies.If Benny has 7 cups of flour, then
Amanda [17]

Answer:

With 7 cups of flour  3.13 batches of cookies can be made.

Step-by-step explanation:

The amount of flour needed per batch of cookies = 7/3 cups

=  2.33 cup

⇒ 1 batch of cookies = 2.33 cup of flour

or  the ratio of <u>cookie to flour =         1       :      2.33</u>

<u />

Now, the amount of flour Benny has = 7 cups

Let the total batches of cookie made = m

or, ratio of <u>cookie to flour =         m       :      7</u>

So, by the RATIO OF PROPORTIONALITY:

\frac{1}{2.23}  = \frac{m}{7 }

⇒ m = 7 /2.23

or, m   =  3.13

or,  total batches of cookie made = 3.13

Hence, from 7 cups of flour  3.13 batches of cookies can be made.

8 0
3 years ago
HELP Use either law of sines or law of cosine. Need help on this problem! show work please!​
Marina86 [1]

Answer: x = 15.035677095729 approximately

Round this however you need to.

=================================================

Explanation:

I'm assuming you want to find the value of x, which your diagram is showing to be the length of segment QR.

If so, then we'll need to find the measure of angle Q first. Using the law of sines, we get the following:

sin(Q)/q = sin(R)/r

sin(Q)/PR = sin(R)/PQ

sin(Q)/13 = sin(85)/19

sin(Q) = 13*sin(85)/19

sin(Q) = 0.6816068987

Q = arcsin(0.6816068987) ... or ... Q = 180-arcsin(0.6816068987)

Q = 42.9693397461 ... or ... Q = 137.0306602539

These values are approximate.

----------------

Now if Q = 42.9693397461 approximately, then angle P is

P = 180-Q-R

P = 180-42.9693397461-85

P = 52.0306602539

Similarly, if Q = 137.0306602539 approximately, then,

P = 180-Q-R

P = 180-137.0306602539-85

P = -42.0306602539

A negative angle is not possible, so we'll ignore Q = 137.0306602539

----------------

The only possible value of angle P is approximately P = 52.0306602539

Let's apply the law of sines again to find side p, aka segment QR

sin(P)/p = sin(R)/r

sin(P)/QR = sin(R)/PQ

sin(52.0306602539)/x = sin(85)/19

19*sin(52.0306602539) = x*sin(85)

19*sin(52.0306602539)/sin(85) = x

x = 15.035677095729

This value is approximate.

Round this value however you need to.

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The difference of twice a number and 2 is at least −26.
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